Work around for "Bignum out of Float range"?


#1

Hi!

First, some codes.


def calc(n)
(2 ** n) * (5 ** 0.5)
end

puts calc(10000)
=>warning: Bignum out of Float range

I understand what the problem is.
If I want to get the result, how can I work around the barrier?

Thanks.
Sam


#2

On 2/2/06, Sam K. removed_email_address@domain.invalid wrote:

If I want to get the result, how can I work around the barrier?

here’s some hacky code which returns a 2-element array
the first number is the significant digits and the second number is
the exponent:

def calc(n)
exp=0
val = (2 ** n)
while val3 > 1e290.to_i
val/=10
exp+=1
end
val =(5**0.5)
unless val.to_s.grep(/(.
)e+(.
)/).empty?
val = $1.to_f
exp+=$2.to_i
end
[val, exp]
end

p calc 1
p calc 10
p calc 100
p calc 1000
p calc 10000

[4.47213595499958, 0]
[2289.73360895978, 0]
[2.83455291382873, 30]
[2.39596608414461, 301]
[4.46109674874798, 3010]

-Adam