Word_wrap method for String?


#1

Hi all,

For a text adventure program I’m working on I needed a method to word
wrap a long string based on spaces or non-word characters so I came up
with this. I just thought I’d post it to see if there are any thoughts
or if there might be a better way to do it.

class String
def word_wrap(width)
source = self.dup
original_width = width
while width < source.length do
last_space = source.rindex( / |\W/, width )
source.insert( last_space, “\n” )
source.gsub!(/\n */,"\n")
width = last_space + original_width
end
source
end
end

Jeff C.man


#2

here’s a (partially modded) excerpt from a previous discussion on this
topic:

width = 11
str = ‘This is a test of the emergency broadcasting servicings I
asseverate’
p str.scan(/\S.{0,#{width}}\S(?=\s|$)|\S+/)


#3

For a text adventure program I’m working on I needed a method
to word wrap a long string based on spaces or non-word
characters so I came up with this. I just thought I’d post
it to see if there are any thoughts or if there might be a
better way to do it.

I wrote one last week, actually

def wrap(wrap_len=78)
start_pos = wrap_len
while start_pos < @fact.length
sp = @fact.rindex(’ ', start_pos)
@fact.insert(sp, ‘|’)
start_pos = sp + wrap_len + 1
end
@fact.gsub!(/|[\s]/, “\n”)
end

I’m far from an expert, so I don’t know which method may be better :slight_smile:

-M


#4

Lou V. wrote:

here’s a (partially modded) excerpt from a previous discussion on this
topic:

width = 11
str = ‘This is a test of the emergency broadcasting servicings I
asseverate’
p str.scan(/\S.{0,#{width}}\S(?=\s|$)|\S+/)

When I was writing that I just KNEW there must be some one-line solution
involving regular expressions!

Although I don’t quite follow the exact structure of this one, it
definitely works…

Jeff


#5

Mike wrote:

For a text adventure program I’m working on I needed a method
to word wrap a long string based on spaces or non-word
characters so I came up with this. I just thought I’d post
it to see if there are any thoughts or if there might be a
better way to do it.

I wrote one last week, actually

def wrap(wrap_len=78)
start_pos = wrap_len
while start_pos < @fact.length
sp = @fact.rindex(’ ', start_pos)
@fact.insert(sp, ‘|’)
start_pos = sp + wrap_len + 1
end
@fact.gsub!(/|[\s]/, “\n”)
end

I’m far from an expert, so I don’t know which method may be better :slight_smile:

-M

class String
# Wrap string by the given length, and join it with the given
character.
# The method doesn’t distinguish between words, it will only work based
on
# the length. The method will also strip and whitespace.
#
def wrap(length = 80, character = $/)
scan(/.{#{length}}|.+/).map { |x| x.strip }.join(character)
end
end

puts ‘Hello, World! I am quite very long :)’.wrap(15, “
\n”)

Output:

Hello, World! I

am quite very

long :slight_smile:

Have fun =)

  • Matt

#6

Lou V. wrote:

everthing old is new again.
you might also want to compare speeds. Yours might be faster.
-lv

It’s my first time using the profiler, but if I’m reading this
correctly–

It took my version 27 seconds to do 6000 word_wraps. Your regexp
version did the same in 2.4 seconds :slight_smile:

Jeff C.man


#7

everthing old is new again.
you might also want to compare speeds. Yours might be faster.
-lv


#8

On Mar 13, 2006, at 1:56 PM, Jeff C.man wrote:

For a text adventure program I’m working on I needed a method to word
wrap a long string based on spaces or non-word characters so I came up
with this. I just thought I’d post it to see if there are any
thoughts
or if there might be a better way to do it.

This one is taken from facets[1]. I use it to wrap lines in TextMate.

def word_wrap(text, col_width=80)
text.gsub!( /(\S{#{col_width}})(?=\S)/, '\1 ’ )
text.gsub!( /(.{1,#{col_width}})(?:\s+|$)/, “\1\n” )
text
end

[1] gem install facets

– Daniel


#9

Lou V. wrote:

here’s a (partially modded) excerpt from a previous discussion on this topic:

width = 11
str = ‘This is a test of the emergency broadcasting servicings I asseverate’
p str.scan(/\S.{0,#{width}}\S(?=\s|$)|\S+/)

When you modded, you didn’t notice that 8 was 2 less than the width.

str =
‘This is a test of the emergency broadcasting servicings I asseverate’
p str.scan(/\S.{0,#{width-2}}\S(?=\s|$)|\S+/)


#10

yahtzee!
btw, this isn’t my regex. Like most things of mine, they’re
either cribbed, borrowed, or outright stolen.
-lv