What does noutput mean in a FFT block whic fft_len=2048?

hi,
i want deal the data after FFT in my own block,i copy a
fft_lensizeof(gr_complex) length of data from in to a buffer,then deal
the data ,and copy the dealed data from buffer to the out,
in a FFT blocks,if there is
size_t block_size=output_signature()->sizeof_stream_item(0);
when i use memcpy(out,in,block_size
noutput ); it works normally ,
but when i do it like this :memcpy(out,in, fft_len*sizeof(gr_complex)
);,it does not work

does the result of block_sizenoutput have any relations with
fft_len
sizeof(gr_complex)
or some other suggestions
thanks,
BZS

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Hi BZS,
you’re mixing concepts here: the FFT len is your FFT size, but noutput
is the number of items you are allowed to produce (maximum).
Please re-read the writing an out-of-tree module wiki page to
understand the difference better :slight_smile:

Greetings,
Marcus

On 10.03.2014 03:21, ??? wrote:

does the result of block_sizenoutput have any relations with
fft_len
sizeof(gr_complex) or some other suggestions thanks, BZS

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