Hello,
Is there an easy way to chop (as in String#chop) a string that can
potentially contain UTF-8 in ruby 1.8? Or should I roll my own?
Thanks,
Ammar
Ended up making my own. Posting it here for the benefit of others, and
maybe some feedback.
UTF-8 aware string chop · GitHub
Regards,
Ammar
On Nov 3, 2010, at 9:08 AM, Ammar A. wrote:
Is there an easy way to chop (as in String#chop) a string that can
potentially contain UTF-8 in ruby 1.8? Or should I roll my own?
Well, it should be this simple:
str.gsub(/.\z/mu, “”)
James Edward G. II
On Wed, Nov 3, 2010 at 5:57 PM, James Edward G. II
[email protected] wrote:
Well, it should be this simple:
str.gsub(/.\z/mu, “”)
On Wed, Nov 3, 2010 at 6:04 PM, Adam P. [email protected]
wrote:
s.gsub(/^(.+)./u) { $1 }
=> “one two thre”
Beautiful. Thank you both.
It was a god exercise for me, so I don’t necessarily feel that I
wasted 30 minutes of my life 
By the way, the m options seems superfluous in James’ version. I get
the same results without it.
Thanks again,
Ammar
On Nov 3, 2010, at 11:33 AM, Ammar A. wrote:
Beautiful. Thank you both.
It was a god exercise for me, so I don’t necessarily feel that I
wasted 30 minutes of my lifeBy the way, the m options seems superfluous in James’ version. I get
the same results without it.
It’s not:
“\n”.sub(/.\z/u, “”)
=> “\n”“\n”.sub(/.\z/mu, “”)
=> “”
Using gsub() over sub() was a dumb mistake on my part though. sub() is
all you need, since it can only match once.
James Edward G. II
I was going to say
$KCODE=“U”
=> “U”s = “one two three”
=> “one two three”s.gsub(/^(.+)./u) { $1 }
=> “one two thre”
I guess I overthought it, huh!
On Wed, Nov 3, 2010 at 6:38 PM, James Edward G. II
[email protected] wrote:
Using gsub() over sub() was a dumb mistake on my part though. sub() is all you
need, since it can only match once.
Thanks for the clarification.
My method now looks like:
def chop_utf8(s)
return unless s
lead = s.sub(/.\z/mu, “”)
last = s.scan(/.\z/mu).first
last = ‘’ unless last
[lead, last]
end
Short and sweet.
Cheers,
Ammar
On Nov 3, 2010, at 11:56 AM, Ammar A. wrote:
My method now looks like:
def chop_utf8(s)
return unless slead = s.sub(/.\z/mu, “”)
last = s.scan(/.\z/mu).first
last = ‘’ unless last
The two lines above can be replaced with the more efficient:
last = s[/.\z/mu] || ‘’
[lead, last]
end
James Edward G. II
On Wed, Nov 3, 2010 at 7:00 PM, James Edward G. II
[email protected] wrote:
The two lines above can be replaced with the more efficient:
last = s[/.\z/mu] || ‘’
At this rate the method is going to disappear.
I updated the gist accordingly:
UTF-8 aware string chop. (the firs gist was posted as anonymous) · GitHub
Thanks again,
Ammar
On Thu, Nov 4, 2010 at 1:25 AM, Ammar A. [email protected] wrote:
On Wed, Nov 3, 2010 at 7:00 PM, James Edward G. II
last = s[/.\z/mu] || ‘’
I updated the gist accordingly:
UTF-8 aware string chop. (the firs gist was posted as anonymous) · GitHub
can we make that a one pass?
str =~ /.\z/mu
[$`,$&]
best regards -botp
Ammar A. wrote in post #959047:
By the way, the m options seems superfluous in James’ version. I get
the same results without it.
foo = “abc\n”
=> “abc\n”foo.sub(/.\z/mu, ‘’)
=> “abc”foo.sub(/.\z/u, ‘’)
=> “abc\n”
On Thu, Nov 4, 2010 at 4:37 PM, Brian C. [email protected]
wrote:
Ammar A. wrote in post #959047:
By the way, the m options seems superfluous in James’ version. I get
the same results without it.foo = “abc\n”
=> “abc\n”
foo.sub(/.\z/mu, ‘’)
=> “abc”
foo.sub(/.\z/u, ‘’)
=> “abc\n”
James clarified this earlier. But thanks for chiming in nonetheless.
Cheers,
Ammar