Using regular expressions


#1

I have the following code:

require ‘open-uri’
def scrape_table(html)
%r{</thead.?>(.?)}m =~html
$1
end

def scrape_case(a_line)
%r{(<a\s.*?\d{6}-\d{2}’>\d{6}-\d{2}</a>)}m =~ a_line
$1
end

if $0 == FILE

url = 'http://localhost:8080/tests/raw.html';
page = open(url)  #open the url like a file
text = page.read; #read it into one string
my_table = scrape_table(text) #grab or "scrape" the table
my_link = scrape_case(my_table) #grab a html that includes a 6-2

digit number (ex: 080910-15)
puts(my_table) #prints out my_table – which contains the table
information
puts("\n")
puts(my_link)

end

The code grabs the one table contained in my URL then looks for an
HTML link that includes a number that is 6 digits, followed by a dash,
followed by 6 digits. I’m fairly certain the regex in scrape_case( )
grabs more than one html link, if more than one is in the table. Is
there any way I can grab all those links into an array?


#2

On 2008.11.11., at 14:22, soldier.coder wrote:

$1
end

Is there any way I can grab all those links into an array?

Sure - String#scan is your friend:

def scrape_case(a_line)
a_line.scan(/<a\s.*?\d{6}-\d{2}’>\d{6}-\d{2}</a>/)
end

ex:

123456-78 here is another: 111111-99”.scan(/<a\s.*?\d{6}-\d{2}’>\d{6}-\d{2}<
/a>/)
=> [“123456-78”, “111111-99”]

HTH,
Peter