Using a variable with gsub & sub

Ruby
1

In the following statement, I’m replacing , with ,NULL,.

$inrec = $inrec.sub(’,\’,’,NULL,’)

What I want to do is something like this:

$inrec = $inrec.sub(’,\’,’,$variable,’)

Unfortunately, I haven’t been able to figure out the syntax for using a
variable with sub & gsub. Can someone help me out?
Thanks.

2

On Nov 15, 3:34 pm, Peter V. [email protected] wrote:

In the following statement, I’m replacing , with ,NULL,.

$inrec = $inrec.sub(‘,\’,‘,NULL,’)

What I want to do is something like this:

$inrec = $inrec.sub(‘,\’,‘,$variable,’)

Unfortunately, I haven’t been able to figure out the syntax for using a
variable with sub & gsub. Can someone help me out?

$inrec.gsub! ‘,\’, “,#{$variable},”

Though I’m not sure why you have the \ in there, unless it just
didn’t end up on the newsgroup correctly.

3

On Fri, Nov 16, 2007 at 06:34:16AM +0900, Peter V. wrote:

Thanks.
The replacement is simply a string, so you could do:

$inrec = $inrec.sub(’,\’,’,’+$variable+’,’)

or

$inrec = $inrec.sub(’,\’,’,#{$variable},’)

4

yermej,
Your solution was exactly what I needed, thanks. As for the \, that is
part of the first value that is being replaced. The first backslash is
an escape character for the second backshash.
Thanks again,
PETERV

yermej wrote:

On Nov 15, 3:34 pm, Peter V. [email protected] wrote:

In the following statement, I’m replacing , with ,NULL,.

$inrec = $inrec.sub(‘,\’,‘,NULL,’)

What I want to do is something like this:

$inrec = $inrec.sub(‘,\’,‘,$variable,’)

Unfortunately, I haven’t been able to figure out the syntax for using a
variable with sub & gsub. Can someone help me out?

$inrec.gsub! ‘,\’, “,#{$variable},”

Though I’m not sure why you have the \ in there, unless it just
didn’t end up on the newsgroup correctly.

5

Peter V. wrote:

$inrec.gsub! ‘,\’, “,#{$variable},”

Though I’m not sure why you have the \ in there, unless it just
didn’t end up on the newsgroup correctly.

If you really want to use global variables ($var) then you can also do

$inrec.gsub!(’,\’, “,#$variable,”)

6

On Nov 16, 2007 6:34 AM, Peter V. [email protected]
wrote:

What I want to do is something like this:

$inrec = $inrec.sub(‘,\’,‘,$variable,’)

Unfortunately, I haven’t been able to figure out the syntax for using a
variable with sub & gsub. Can someone help me out?

Try this.

“,#{var},”

Harry