Using a Regexp in String#gsub in C

Ruby
1

Hi,

I’ve got some code in C that makes a call to String#gsub via rb_funcall

VALUE pattern = rb_str_new2(" “);
VALUE heading = rb_funcall(str, rb_intern(“gsub”), 2, pattern,
rb_str_new2(”-"));

I’d like to get pattern to be a Regexp object so that I can replace
repeating whitespace, but the various things I’ve tried so far haven’t
worked. I’ve tried:

VALUE pattern = rb_str_new2("/\s\+/");

and

VALUE pattern = RREGEXP(rb_str_new2("\s\+"))’

Would someone out there be able to help me out with this?

Thanks

2

You can create the string first (without slashes), then create the
regexp using the string, finally call gsub as usual, passing the regexp
value.

For example:

VALUE pattern = rb_str_new2(“some-pattern”);
VALUE regex = rb_reg_new_str(pattern, 0);

Hope that helps,
Ammar

3

On Thu, Aug 1, 2013 at 1:58 PM, Ammar A. [email protected] wrote:

Perfect, thanks!

Matt

4

On Thu, Aug 1, 2013 at 3:41 PM, Ryan D. [email protected]
wrote:

Why not just use rb_reg_new ?

10003 % ag rb_reg_new include/
include/ruby/intern.h
635:VALUE rb_reg_new_str(VALUE, int);
636:VALUE rb_reg_new(const char *, long, int);

That’s even better. Thanks!

5

On Aug 1, 2013, at 11:58 , Ammar A. [email protected] wrote:

You can create the string first (without slashes), then create the regexp using
the string, finally call gsub as usual, passing the regexp value.

For example:

VALUE pattern = rb_str_new2(“some-pattern”);
VALUE regex = rb_reg_new_str(pattern, 0);

Why not just use rb_reg_new ?

10003 % ag rb_reg_new include/
include/ruby/intern.h
635:VALUE rb_reg_new_str(VALUE, int);
636:VALUE rb_reg_new(const char *, long, int);