To_s(base=2) in 1.8 only?

tststs · January 16, 2009, 10:25am

f.each_byte {|x| print x.to_s(base=2).rjust(8,‘0’)

the above will fail in 1.6.4

wanna ask if to_s(base=2) is only available in 1.8?

my intention is to get each byte and output it as 10101010 format. Is
there any way that i can do that in 1.6.4?

thank you.

tststs · January 16, 2009, 10:34am

On Fri, Jan 16, 2009 at 10:23 AM, ts removed_email_add[email protected] wrote:

I cannot test with 1.6.4 but probably the following works

“%b” % x

Pas d’quoi
R.

tststs · January 16, 2009, 4:10pm

On Fri, 16 Jan 2009 01:21:15 -0800, ts wrote:

f.each_byte {|x| print x.to_s(base=2).rjust(8,‘0’)

Can’t speak to the Ruby 1.6 issue, but the base= doesn’t add anything to
your code (it just assigned 2 to a local variable). Just call x.to_s(2)

–Ken