I’m writing a block that always outputs the same number of items as it
The block is doing FFT on a fixed length vector, so I always need nfft
samples in and nfft samples out. I’ve achieved this (I think) by using:
set_min_noutput_items(nfft) and set_max_noutput_items(nfft). However,
I increase nfft to 8192, I get a message about not enough buffer space.
tested various things and ended up calling
set_min_output_buffer(2*nfft) as just nfft wasn’t enough. It all seems
work nicely, except that the rx_time tags are screwed up – I get a
random offset in the beginning, even though there are no dropped packets
Is this a bug or a feature? What is the correct way to increase the
of noutput_items without breaking rx_time tags?
On 10/09/2013 02:59 PM, Juha V. wrote:
set_min_output_buffer(2*nfft) as just nfft wasn’t enough. It all
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An easier way to achieve this is, is calling set_output_multiple(nfft)
in the block constructor - which assures noutput_items = n*nfft where n
then if its a sync block without the relative rate or forecast being
change, it will also assume it also needs nfft items each work call
set_min_noutput_nitems and set_min_output_buffer are bigger hammers that
probably shouldn’t be used in this case unless you have really big
vectors - I think by default there should be no problems with an output
multiple <= 8k
are you consuming nfft each time in your current block? If it is
providing you nfft+extra samples each time through work you would get
strange offsets if you simply consumed noutput_items each time.
I’ve modified the code. I now call set_output_multiple(nfft) in the
constructor. This is probably for the better, as I can now use
again. I also got rid of the buffer size error message on larger fft
However, I still have the problem with random rx_time tags triggered in
beginning of the acquisition. I’ll keep investigating this. It could be
that this is a feature of the n200 + gpsdo combination.