Side-stepping the debate about running exponential regular expressions
first place, I’d like to catch a long running regex using
Timeout.timeout():
$ ruby -v && irb -r timeout
ruby 1.8.4 (2005-12-24) [i486-linux]
irb(main):001:0> Timeout.timeout 5 do ("a"300)+“b” =~ /^(a)*$/ end
Except that it appears the mechanism the Timeout module uses can’t seem
to do this. After looking at the source of Timeout.timeout(), it seems
that the regex is blocking all threads and disallowing the Timeout
mechanism from detecting the runaway block. Indeed, the following
never returns:
irb(main):002:0> t = Thread.new do ("a"300)+“b” =~ /^(a)*$/ end
A few questions:
- Why do regexes seem to stop up all threads? Is this fixed in ruby
1.9? - Is there a way to offload this processing into another thread
without resorting to DRb? - Is there a better way to detect this sort of thing?