Syntax problem: @var=="v" ? { ... } : { ... }

Ruby
1

Hi All

I tried to print an “M” or “V” depending on the value of a variable,
like

@var = “v”
@var == “v” ? { p “V” } : { p “M” }

this however doesn’t work, but I’m sure something like this can be done!
Any suggestions ?

Cheers
LuCa

2

Alle Friday 15 February 2008, Luca S. ha scritto:

Cheers
LuCa

p(@var == “v” ? “V” : “M”)

Stefano

3

Luca S. wrote:

@var = “v”
@var == “v” ? { p “V” } : { p “M” }

this however doesn’t work, but I’m sure something like this can be done!
Any suggestions ?

Leave out the curlies.

4

Alle Friday 15 February 2008, Sebastian H. ha scritto:

Luca S. wrote:

@var = “v”
@var == “v” ? { p “V” } : { p “M” }

this however doesn’t work, but I’m sure something like this can be done!
Any suggestions ?

Leave out the curlies.

And put brackets around the arguments of p, otherwise you’ll get a
syntax
error

Stefano

5

thnx, that works, but what if I want to do 2 or more actions/statements
for each options ?

@var == “v” ? P(“V”);do_something(“V”) : …

suggestions ?

Stefano C. wrote:

Alle Friday 15 February 2008, Sebastian H. ha scritto:

Luca S. wrote:

@var = “v”
@var == “v” ? { p “V” } : { p “M” }

this however doesn’t work, but I’m sure something like this can be done!
Any suggestions ?

Leave out the curlies.

And put brackets around the arguments of p, otherwise you’ll get a
syntax
error

Stefano

6

Alle Friday 15 February 2008, Luca S. ha scritto:

thnx, that works, but what if I want to do 2 or more actions/statements
for each options ?

@var == “v” ? P(“V”);do_something(“V”) : …

suggestions ?

In this case, I’d use a standard if:

if @var == “v”
p “V”
do_something
else
do_something_else
end

Stefano