Syntax error with array interpolation

Ruby
1

Below is a code snippet which gives me some headache:

def headache
yield(*(foo(1)),“bar”)
end

def foo(n)
[n,n+2,n+5]
end

headache { |a,b,c,d| puts a.to_s; puts b.to_s; puts c.to_s; puts d }

I had expected that this would print

1
3
6
bar

But Ruby 1.8.5 complains:

./headache.rb: line 1: def: command not found
./headache.rb: line 2: syntax error near unexpected token *' '/headache.rb: line 2: yield(*(foo(1)),“bar”)

and Ruby 1.8.6 complains:

H:/tmp/headache.rb:2: syntax error, unexpected tSTRING_BEG, expecting
tAMPER
yield(*(foo(1)),“bar”) ^
H:/tmp/headache.rb:2: syntax error, unexpected ‘)’, expecting kEND
H:/tmp/headache.rb:10: syntax error, unexpected $end, expecting kEND

There must something be wrong with the way I’m doing array
interpolation,
but I can’t spot the error…

Ronald

2

Ronald F. wrote:

Below is a code snippet which gives me some headache:

def headache
yield(*(foo(1)),“bar”)
end

You can’t use a ‘splatted’ array anywhere in a method call except at the
end:

def foo(a, b, c)
p [a, b, c]
end

foo(1, 2, *[3]) #=> works
foo(1, *[3], “asdf”) #=> doesn’t work

I’m not quite sure why this should be, since it has an unambiguous
meaning, unlike defining a method with a splat in the middle of the
arguments:

def bar(a, *b, c=0)
…
end

The splat operator is a bit mysterious to me in this regard…

best,
Dan

3

Daniel L. wrote:

You can’t use a ‘splatted’ array anywhere in a method call except at the
end:

Pardon me: and before a block argument:
foo(1, 2, *[3], &block)

Dan