Super.index gives error

Hello!
I’m having a strange problem.

class Super

def index
puts “some code”
end
end

class Base < Super

def index
super.index() # Says you super is nil! nil.index and an
error. What might be wrong?
end
end

Hi:

On Feb 19, 2008 9:34 PM, MohsinHijazee [email protected] wrote:

class Base < Super

def index
super.index() # Says you super is nil! nil.index and an
error. What might be wrong?
end
end

irb(main):001:0> class Super
irb(main):002:1> def index
irb(main):003:2> puts “some code”
irb(main):004:2> end
irb(main):005:1> end
=> nil
irb(main):006:0> class Sub < Super
irb(main):007:1> def index
irb(main):008:2> super
irb(main):009:2> end
irb(main):010:1> end
=> nil
irb(main):011:0> Sub.new.index
some code
=> nil
irb(main):012:0>

Technically, Super is also the base' class, so I named it Sub. Just usesuper’ – super calls the method of the same name in the superclass.

HTH
Arlen

On Feb 19, 3:38 pm, Arlen C. [email protected] wrote:

 super.index()    # Says you super is nil! nil.index and an

irb(main):006:0> class Sub < Super
Technically, Super is also the base' class, so I named it Sub. Just usesuper’ – super calls the method of the same name in the superclass.

HTH
Arlen

Thank you very much! The problem is solved