Strings to int conversion

Ruby
1

s = “1234” [0…1]
p s #> “12”
p s.to_i #> 12
s = s[1]
p s #> 50
p s.to_i #> 50

I can see the reason for this happening, but I don’t want it to happen.

So how do I make it return 2 instead of 50?

2

On Sat, Jun 27, 2009 at 05:55:20AM +0900, Peter Wu wrote:

s = “1234” [0…1]
p s #> “12”
p s.to_i #> 12
s = s[1]
p s #> 50
p s.to_i #> 50

I can see the reason for this happening, but I don’t want it to happen.

So how do I make it return 2 instead of 50?

“1234”.split(’’)[1].to_i # => 2

3

Peter Wu wrote:

s = “1234” [0…1]
p s #> “12”
p s.to_i #> 12
s = s[1]
p s #> 50
p s.to_i #> 50

I can see the reason for this happening, but I don’t want it to happen.

So how do I make it return 2 instead of 50?

s[1,1]
s[1…1]

4

Thanks, guys.

5

Hi,

Am Samstag, 27. Jun 2009, 05:55:20 +0900 schrieb Peter Wu:

s = “1234” [0…1]
s = s[1]
p s #> 50

I can see the reason for this happening, but I don’t want it to happen.

The answer has already been given.

As far as I know Ruby 1.9 returns “2”.

There’s another [] operator that’s not well known:

16[4] #=> 1 (the 4th bit is 1)

Bertram

6

Hi –

On Sat, 27 Jun 2009, Peter Wu wrote:

s = “1234” [0…1]
p s #> “12”
p s.to_i #> 12
s = s[1]
p s #> 50
p s.to_i #> 50

I can see the reason for this happening, but I don’t want it to happen.

So how do I make it return 2 instead of 50?

Addendum to other answers:

In 1.9 it returns the character rather than the character code.

David

7

One of Ruby’s problems is that it invites clever solutions, which are
computationally costly and create undue amounts of garbage.

How about

?> “1234”[1].chr
=> “2”

Cheers,

Bob Schaaf

8

Bertram S. wrote:

There’s another [] operator that’s not well known:

16[4] #=> 1 (the 4th bit is 1)

Wow, I’ve been using ruby for many years but there’s
always something new to learn isn’t it? Thanks.

Daniel

9

Peter Wu-5 wrote:

So how do I make it return 2 instead of 50?

p s[1].chr.to_i #=> 2