From: Richard Zenn [mailto:[email protected]]

# Here is an array s = [“aaa”, “b”, “c”, “d”, “ee”, “f”]

# I want to combine them with some rules

# 1.

# s[i].size > s[i+1].size

# combine them

# 2.

# s[i+1].size > s[i].size

# combine them

rules 1 & 2 simply says that if they differ in size, combine them, no?

# 3.

# s[i].size + s[i+1].size

where is the condition here?

add the sizes?? it does not show in your output below

# The upper result is

# {“aaab”}

# {“bc”}

# {“bcd”}

# {“cd”}

# {“dee”}

# {“eef”}

hmmm, it seems that you are combining them regardless… ??

here is a simplistic code (judging only fr your output)

[email protected]:~$ cat test.rb

s = [“aaa”, “b”, “c”, “d”, “ee”, “f”]

t = []

(1…s.size-2).each do |i|

t << s[i-1] + s[i]

if s[i].size == s[i-1].size and s[i].size ==s[i+1].size

t << s[i-1]+s[i]+s[i+1]

end

t << s[i] + s[i+1]

end

p t.uniq

[email protected]:~$ ruby test.rb

[“aaab”, “bc”, “bcd”, “cd”, “dee”, “eef”]

i hope that is ok to startup your ruby interest.

next time, pls show your initial/tried code, no matter how wrong it is

you think. help us help you, ie.

kind regards -botp