Thanks for some of your replies for the lst post i need small
modification in that post … i want to sort the salary in descending
order. i have explained the same quesion again…
Hi all,
I want to sort the objects of array based on two attributes.I want
sort an employee class based on his salary in descecding order and name
, so that if two
person has same salary it should be sorted with name.
Lets say for example the employee objects has following name and
salary.
name salary
d 100
c 200
b 50
a 100
so in this case the result which i expect is
name salary
b 200
a 100
d 100
c 50
Note:In the above example for salary 100 the sorting is done
alphabetically, but initially(before sorting) ‘d’ came first and then
‘a’ came.so basically i want to sort the array with more than one order.
Can any one help me to solve it ??
senthil wrote:
salary.
name salary
b 200
a 100
d 100
c 50
Note:In the above example for salary 100 the sorting is done
alphabetically, but initially(before sorting) ‘d’ came first and then
‘a’ came.so basically i want to sort the array with more than one order.
Can any one help me to solve it ??
In this case, just invert the salary:
sorted_employees = employees.sort_by { |e| [ -e.salary, e.name ] }
I can’t think of a way offhand to have different lexicographic orderings
in the same sort, though.
senthil wrote:
Thanks for some of your replies for the lst post i need small
modification in that post … i want to sort the salary in descending
order. i have explained the same quesion again…
I came up with this which is sub par as I test for a condition twice so
stay tuned for a better solution…
irb(main):001:0> [[‘d’,100],[‘c’,200],[‘b’,50],[‘a’,100]].sort {|a,b|
b[1]==a[1]?a[0]<=>b[0]:b[1]<=>a[1]}
=> [[“c”, 200], [“a”, 100], [“d”, 100], [“b”, 50]]
hope this helps
ilan
Alex Y. wrote:
sorted_employees = employees.sort_by { |e| [ -e.salary, e.name ] }
I can’t think of a way offhand to have different lexicographic orderings
in the same sort, though.
Doh!!! Ofcourse! Ok… more coffee for me…
ilan
On Mar 26, 2007, at 10:18 AM, Ilan B. wrote:
irb(main):001:0> [[‘d’,100],[‘c’,200],[‘b’,50],[‘a’,100]].sort {|a,b|
b[1]==a[1]?a[0]<=>b[0]:b[1]<=>a[1]}
=> [[“c”, 200], [“a”, 100], [“d”, 100], [“b”, 50]]
hope this helps
ilan
Just to add a bit to this: consider using .nonzero? for chained
comparisons
[[‘d’,100],[‘c’,200],[‘b’,50],[‘a’,100]].
sort {|a,b| (b[1]<=>a[1]).nonzero? || a[0]<=>b[0] }
-Rob
Rob B. http://agileconsultingllc.com
[email protected]
On 3/26/07, Alex Y. [email protected] wrote:
Lets say for example the employee objects has following name and
In this case, just invert the salary:
sorted_employees = employees.sort_by { |e| [ -e.salary, e.name ] }
I can’t think of a way offhand to have different lexicographic orderings
in the same sort, though.
Someone, in another recent thread, came up with the idea of a reverse
proxy class something like this
class Reverse
:attr_reader :obj
def initialize(obj)
@obj = obj
end
def <=>(other)
other.obj <=> self.obj
end
end
so let’s say you wanted to sort the names in descending order as well:
sorted_employees = employees.sort_by { |e| [-e.salary,
Reverse.new(e.name) ] }
You could even use this “reverse” proxy to change the sorting of
salary, so that the original could be:
sorted_employees = employees.sort_by { |e| [ Reverse.new(e.salary),
e.name ] }
One could quibble about the name Reverse.
–
Rick DeNatale
My blog on Ruby
http://talklikeaduck.denhaven2.com/