Single php file location match

How would I go about running a PHP file that is only matched by the
request of that file? Meaning, how can someone request a file and nginx
run this configuration ONLY when this PHP file is requested.

Here is what I have so far:

location / {
root /www/default/;
try_files $uri $uri/ /index.php?q=$uri&$args;
index index.php;
}

location /status.php {
#allow 192.168.1.0/24;
deny all;
#allow all;
root /www/default/;
try_files $uri $uri/ /index.php?q=$uri&$args;
index status.php;
}

Basically, I’ll be setting up rules to only allow a local network
request, but only for status.php. So how do I go about allowing this
one network to status.php?

Posted at Nginx Forum:
http://forum.nginx.org/read.php?2,60179,60179#msg-60179

On Thu, Mar 04, 2010 at 11:34:19PM -0500, drewrockshard wrote:

Basically, I’ll be setting up rules to only allow a local network request, but only for status.php. So how do I go about allowing this one network to status.php?
location = /status.php {
#allow 192.168.1.0/24;
deny all;
#allow all;
root /www/default/;
fastcgi_pass …
include fastcgi.conf;
}


Igor S.
http://sysoev.ru/en/

Igor,

Thanks for the update! This resolved it. So, after I had submitted my
post I did end up using the equal sign ("="), which worked, however, it
wasn’t working, but after inserting the fcgi stuff, it worked.

Thanks again!

Posted at Nginx Forum:
http://forum.nginx.org/read.php?2,60179,60301#msg-60301

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