Should hash equality ignore default values?

Hash equality right now ignores the default values.
So a == b may be true even if a[0] == b[0] would be false.

Is this behaviour intended ?

irb(main):001:0> a =
=> {}
irb(main):002:0> b =
=> {}
irb(main):003:0> a == b
=> true
irb(main):004:0> a[0] == b[0]
=> false
irb(main):005:0> c ={|ht,k| ht[k] = 5}
=> {}
irb(main):006:0> a == c
=> true
irb(main):007:0> a[0] == c[0]
=> false

On 5/7/07, Tomasz W. [email protected] wrote:

=> true

Tomasz W. [ ]

Good question Tomasz and furthermore…
=> {}
=> {}
irb(main):008:0> h==g
=> true
irb(main):009:0> h[1] ### We just must not forget that this is an
=> 1
irb(main):010:0> h==g
=> false

The second result of the comparision is clear h== {1 =>1} and g=={}

although this might be surprising I think it is about ok, without this
we could not compare to literals…
tough call though
I am eager to hear other opinions.


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