hunt
#1
var text=“Afganistan (+86)”
var code=text.sub(/\w+/, ‘’)
result: code = (+86)
var text = “Antigua and Barbuda (+1268)”
var code=text.sub(/\w+/, ‘’)
result : code = and Barbuda (+1268)"
what regular expression I can try to get second one as first. ie (+1268)
hunt
#2
HUNT HUNT wrote:
var text=“Afganistan (+86)”
var code=text.sub(/\w+/, ‘’)
result: code = (+86)
var text = “Antigua and Barbuda (+1268)”
var code=text.sub(/\w+/, ‘’)
result : code = and Barbuda (+1268)"
what regular expression I can try to get second one as first. ie (+1268)
Do you want “(+1268)” from the second query? If so, does
var code=text.sub(/[\w+ ]/, ‘’)
work? See http://rubular.com/r/g5I6tYxb5C for where I show it works.
Thanks,
ben
hunt
#3
“Antigua and Barbuda (+1268)”.scan(/\d+/).to_s
=> 1268
“Antigua and Barbuda (+1268)”.scan(/(+\d+)/).to_s
=> (+1268)
hunt
#4
Hi –
On Tue, 27 Apr 2010, Vladimir R. wrote:
“Antigua and Barbuda (+1268)”.scan(/\d+/).to_s
=> 1268
“Antigua and Barbuda (+1268)”.scan(/(+\d+)/).to_s
=> (+1268)
There’s a nice technique for quickly getting a substring from a
string using a subscript-style notation:
“Antigua and Barbuda (+1268)”[/(+\d+)/] # “(+1268)”
David
–
David A. Black, Senior Developer, Cyrus Innovation Inc.
THE Ruby training with Black/Brown/McAnally
COMPLEAT Coming to Chicago area, June 18-19, 2010!
RUBYIST http://www.compleatrubyist.com
hunt
#6
Vladimir R. wrote:
nice one David!
I did with this
var code=text.sub(/[a-z A-Z]/, ‘’)
hunt
#7
David A. Black wrote:
Hi –
On Tue, 27 Apr 2010, Vladimir R. wrote:
“Antigua and Barbuda (+1268)”.scan(/\d+/).to_s
=> 1268
“Antigua and Barbuda (+1268)”.scan(/(+\d+)/).to_s
=> (+1268)
There’s a nice technique for quickly getting a substring from a
string using a subscript-style notation:
“Antigua and Barbuda (+1268)”[/(+\d+)/] # “(+1268)”
Ooh, nice! Didn’t know about that.
David
Best,
Marnen Laibow-Koser
http://www.marnen.org
[email protected]