[regexp] How to extract

From:

#header h1 a {
display: block;
background: url(images/wordpress-logo.png) center left no-repeat;
width: 301px;
height: 88px;
text-indent: -9999px;
float: left;
}

#header ul li#download a {
background: #d54e21 url(images/download-tab-bg.png) bottom left
repeat-x;
color: #fff;
-moz-border-radius-topleft: 3px;
-khtml-border-top-left-radius: 3px;
-webkit-border-top-left-radius: 3px;
border-top-left-radius: 3px;
-moz-border-radius-topright: 3px;
-khtml-border-top-right-radius: 3px;
-webkit-border-top-right-radius: 3px;
border-top-right-radius: 3px;
text-shadow: #b5421c 1px 1px 1px;
}

i need each occurence of text enclosed between url(************), for
this example:

images/wordpress-logo.png
images/download-tab-bg.png

Jan Kowalski wrote:

From:

#header h1 a {
display: block;
background: url(images/wordpress-logo.png) center left no-repeat;
width: 301px;
height: 88px;
text-indent: -9999px;
float: left;
}

#header ul li#download a {
background: #d54e21 url(images/download-tab-bg.png) bottom left
repeat-x;
color: #fff;
-moz-border-radius-topleft: 3px;
-khtml-border-top-left-radius: 3px;
-webkit-border-top-left-radius: 3px;
border-top-left-radius: 3px;
-moz-border-radius-topright: 3px;
-khtml-border-top-right-radius: 3px;
-webkit-border-top-right-radius: 3px;
border-top-right-radius: 3px;
text-shadow: #b5421c 1px 1px 1px;
}

i need each occurence of text enclosed between url(************), for
this example:

images/wordpress-logo.png
images/download-tab-bg.png

str = <<CSS
#header h1 a {
display: block;
background: url(images/wordpress-logo.png) center left no-repeat;
width: 301px;
height: 88px;
text-indent: -9999px;
float: left;
}

#header ul li#download a {
background: #d54e21 url(images/download-tab-bg.png) bottom left
repeat-x;
color: #fff;
-moz-border-radius-topleft: 3px;
-khtml-border-top-left-radius: 3px;
-webkit-border-top-left-radius: 3px;
border-top-left-radius: 3px;
-moz-border-radius-topright: 3px;
-khtml-border-top-right-radius: 3px;
-webkit-border-top-right-radius: 3px;
border-top-right-radius: 3px;
text-shadow: #b5421c 1px 1px 1px;
}
CSS

pattern = /url((.*))/ #to match a parenthesis escape it with a ‘’

str.each do |line|
match = line[pattern, 1] #1 is the parenthesized sub pattern
if match
puts match
end
end

–output:–
images/wordpress-logo.png
images/download-tab-bg.png

On Fri, Apr 4, 2008 at 8:00 PM, 7stud – [email protected] wrote:

float: left;
-moz-border-radius-topright: 3px;
images/download-tab-bg.png
}
-khtml-border-top-right-radius: 3px;
if match
puts match
end
end

–output:–

images/wordpress-logo.png
images/download-tab-bg.png

You can use a non-greedy multi-line #scan pattern as well…

str.scan /url((.*?))/m
=> [[“images/wordpress-logo.png”], [images/download-tab-bg.png]]

…which you can #flatten if you want.

Todd

7stud – wrote:

pattern = /url((.*))/ #to match a parenthesis escape it with a ‘’

Actually, to be safe make the .* non-greedy:

pattern = /url((.*?))/ #to match a parenthesis escape it with a ‘’

Here’s the difference:

str = “abcurl(good)bad)xyz”

pattern1 = /url((.))/ #to match a parenthesis escape it with a ‘’
pattern2 = /url((.
?))/ #to match a parenthesis escape it with a ‘’

match1 = str[pattern1, 1] #1 is the parenthesized sub pattern
puts match1

match2 = str[pattern2, 1] #1 is the parenthesized sub pattern
puts match2

–output:–
good)bad
good

On 05.04.2008 10:41, Todd B. wrote:

float: left;
-moz-border-radius-topright: 3px;
images/download-tab-bg.png
}
-khtml-border-top-right-radius: 3px;
if match
You can use a non-greedy multi-line #scan pattern as well…

str.scan /url((.*?))/m
=> [[“images/wordpress-logo.png”], [images/download-tab-bg.png]]

…which you can #flatten if you want.

I’d rather use a more specific match as I believe this could be a tad
more efficient

str.scan /url(([^)]*))/m

Cheers

robert

On Sat, Apr 5, 2008 at 3:55 AM, Robert K.
[email protected] wrote:

On 05.04.2008 10:41, Todd B. wrote:

On Fri, Apr 4, 2008 at 8:00 PM, 7stud – [email protected] wrote:

I’d rather use a more specific match as I believe this could be a tad more
efficient

str.scan /url(([^)]*))/m

Yep, I think that’s better.

Todd

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