Regexp: exclude a word or a phrase

Dear all

I am trying to exclude certain text from whole text using regular
expression but the i cannot get it working. I am using this to get the
text between the matches and not the match itself

for example, I have to process output of SVN DIFF and look through it

Index: filename1

text
text
text
text
text
text
Index: filename2

text
text
text
text
Index: filename3

text
text

I want to count how many changed lines in each file, I am thinking of
getting the text between the lines of ========= which actually my target

i tried to use /[^=]+/ and it does not work because it will exclude
statements with equal signs as well which is not my aim

any idea

thanks

On Tue, Apr 20, 2010 at 07:29, Shuaib Z. [email protected]
wrote:

i tried to use /[^=]+/ and it does  not work because it will
exclude statements with equal signs as well which is not my aim

I don’t think I understand your intent, but in order to match
lines other than ones composed solely of =, try /^[^=]+$/

To match a location that does not contain a specific string, you
can try:

/(?!foo)/

this regular expression will match a location that does not
contain the sequence “foo”. Beware! Note that I’m writing
“location”, not “string”. This matches:

"foo" =~ /(?!foo)/ )/     # anything not followed by foo, match

This also matches:

"foobar" =~ /(?!bar)/     # anything not followed by bar, match

You have to anchor it somehow:

"foobar" =~ /foo(?!bar)/  # "foo" not followed by "bar", no match

Marcelo

“Shuaib Z.” [email protected] wrote in message
news:[email protected]

text
text

any idea

thanks

Posted via http://www.ruby-forum.com/.

The regexp /^=+$/ will match a whole line of ‘=’ as in:

re = /^=+$/
count = 0
section = 1
DATA.each_line do |row|
if(re =~ row) then
printf(“section %d has %d records\n”, section, count)
count = 0
section +=1
else count +=1
end # if
end # while
exit(0)
END
text1-
text2=
text3-

text4
text5

Hth gfb

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