Regex: splitting conditionally on |

Ruby
1

I’m parsing mediawiki markup and I’d like to split a multi-line string
on | (vertical-bar), but only if it isn’t contained w/in another
pattern.

| name1 = value1
| name2 = value2 | name3 = value3
| name4 = [[foo|bar]]

I’d like String.split(/pattern/) to return [‘name1 = value1’,‘name2 =
value2’,‘name3 = value3’,‘name4 = [[foo|bar]]’]

I’ve working on a negative look-ahead pattern without success and my
brain is tired.

Thanks for any suggestions

2

On 18.06.2008 00:04, computorist wrote:

I’ve working on a negative look-ahead pattern without success and my
brain is tired.

Thanks for any suggestions

Without testing, something like this might work:

str.scan %r{
(?: [ [^]]* ] | [^|] )+
}xm

Cheers

robert

3

computorist wrote:

I’ve working on a negative look-ahead pattern without success and my
brain is tired.

Thanks for any suggestions

str.split /\s*|\s*(?=\s*\w+\s*=)/
I don’t know whether this exactly meets your requirement, but this will
split
only on |s that are followed by a word and a =. For your sample input
that
gives the desired result.

HTH,
Sebastian

4

On Jun 18, 12:35 am, Sebastian H. [email protected]
wrote:

value2’,‘name3 = value3’,‘name4 = [[foo|bar]]’]

HTH,
Sebastian

Jabber: [email protected]
ICQ: 205544826

This seems to work well. Searching for what I want is better than
excluding the bits I don’t want.

Thanks