Read a xml file

Ruby
1

hello, im new in using rexml and a i have a first question: how can a
read this file:










i want to read all children so that output will be something like that:
drive C
folder folder1
subfolder sub1
subfolder sub2
file file1
file file2
subfoler sub3
folder folder2
file file1
file file2

How can i do that?, Tnx

2

On Nov 23, 2007, at 7:14 AM, Bulhac M. wrote:

hello, im new in using rexml and a i have a first question: how can a
read this file:



[…]

I’d use xml-simple.

% gem install xml-simple

Then a program like this:

require ‘xmlsimple’
require ‘pp’
pp XmlSimple.xml_in(‘xml.xml’)

will produce this structure of hashes and arrays:

{“name”=>“c”,
“folder”=>
[{“name”=>“folder1”,
“subfolder”=>
[{“name”=>“sub1”, “content”=>"\n “},
{“name”=>“sub2”, “file”=>[{“name”=>“file1”}, {“name”=>“file2”}]},
{“name”=>“sub3”, “file”=>[{“name”=>“file1”}]}]},
{“name”=>“folder2”,
“file”=>
[{“name”=>“file1”, “content”=>”\n “},
{“name”=>“file2”, “content”=>”\n "}]}]}

You can customize the printing to suit your taste. There are different
options to xml-simple that let you control the array/hash structure
that gets generated.

Brian M., independent consultant
Mostly on agile methods with a testing slant
www.exampler.com, Exploration Through Example, twitter.com/marick

3

but i want to read that structure of file; i did try with rexml and i
havent figure it out yet

4

Hi,

On 23-Nov-07, at 8:14 AM, Bulhac M. wrote:

folder folder2 file file1 file file2

How can i do that?, Tnx

You’re going to have to work out which ‘parser’ you want to use. I
think there are three in REXML: DOM, SAX, and a pull parser.

Choosing the parser to use is a little tricky, and will depend on what
you plan to do with the parsed XML file.

FWIW, I tend to use either my own pull parser or libxml.

With my thing, xampl-pp (a pull parser), installed as a gem, you’d
write this as:

require “xampl-pp”

def format(filename)
xpp = Xampl_PP.new
xpp.input = File.new(filename)

loop do
case xpp.nextEvent
when Xampl_PP::START_ELEMENT
print " " * (xpp.depth - 1)
print xpp.name
xpp.attributeValue.each { | v | print " #{ v }" }
print “\n”
when Xampl_PP::END_DOCUMENT
break
end
end
end

format(“./test.xml”)

And you’d get exactly the output you wanted.

This is such a simple use of the parser that it is hard to choose
between them.

Cheers,
Bob

–
Posted via http://www.ruby-forum.com/.

Bob H. – tumblelog at
http://www.recursive.ca/so/
Recursive Design Inc. – weblog at
http://www.recursive.ca/hutch
http://www.recursive.ca/ – works on
http://www.raconteur.info/cms-for-static-content/home/

5

On Nov 23, 6:14 am, Bulhac M. [email protected] wrote:

<subfolder  name="sub3">
file file1 file file2

Note that I had to fix your XML - you were missing a closing tag for
one of your files.

def show_item( rexml_element, level=0 )
print " "*level
puts “#{rexml_element.name} #{rexml_element.attributes[‘name’]}”
rexml_element.elements.each{ |el|
show_item( el, level+1 )
}
end

require ‘rexml/document’
doc = REXML::Document.new( DATA.read )

show_item( doc.root )

END


















6

On Nov 23, 6:14 am, Bulhac M. [email protected] wrote:

<subfolder  name="sub3">
file file1 file file2

Note that if your XML is properly indented already, you don’t even
need an XML parser for this particular task:

source = DATA.read

remove explicit closing elements

source.gsub! %r{</.+?>}, ‘’

remove empty lines

source.gsub! %r{^[ \t]+\n}, ‘’

convert tags to desired output

source.gsub! /<(\w+)\s+name=“(.+?)”.+/, ‘\1 \2’

puts source
END