Re: Confusion Over Keyword Arguments


#1

From: Yukihiro M. [mailto:removed_email_address@domain.invalid]

end
or

a = foo( (baz = 5), (bar = 2) )

??

Second one.

Dan


#2

On Fri, 3 Mar 2006, Berger, Daniel wrote:

foo baz = 5, bar = 2

a, b = foo(baz = 5), (bar = 2)

or

a = foo( (baz = 5), (bar = 2) )

??

Second one.

but that’s a problem no? number two is the same as this

baz = 5
bar = 2
a = foo baz, bar

see, when on writes

foo baz = 5, bar = 2

it’s ambiguous if those assignments are part of a method call or not.
bar
escpecitally, it could easily be considered an assignment statement
(bar=2)
that’s part of a parrallel assignment statement.

or am i missing something?

-a


#3

removed_email_address@domain.invalid wrote:

??

Second one.

but that’s a problem no? number two is the same as this

baz = 5
bar = 2
a = foo baz, bar

No, then they become positional. That’s the same as foo 2, 5.

see, when on writes

foo baz = 5, bar = 2

it’s ambiguous if those assignments are part of a method call or not. bar
escpecitally, it could easily be considered an assignment statement (bar=2)
that’s part of a parrallel assignment statement.

or am i missing something?

The parser just has to be trained well enough. :slight_smile:

That being said, perhaps using ‘=’ as a keyword operator would just
cause too
much confusion amongst the Ruby community. I know some people hate
changing
behavior based on context.

Regards,

Dan