Rails 1.2.2 and ranges in AR conditions clause

Rails
1

Hi,

According to Jamis’ blog post:

You can do this in RoR 1.2.2:
Student.find(:all, :conditions => { :grade => 9…12 })

which automatically get converted into:
SELECT * FROM students WHERE grade BETWEEN 9 AND 12

but when I try this:

Customer.find :all, :conditions => [:id => 1…2] # loaded from
fixture customer.yml

I get:

NoMethodError: undefined method %' for {:id=>1..2}:Hash from /usr/local/lib/ruby/gems/1.8/gems/activerecord-1.15.2/lib/active_record/base.rb:1419:in sanitize_sql_array’
from
/usr/local/lib/ruby/gems/1.8/gems/activerecord-1.15.2/lib/active_record/base.rb:1388:in
sanitize_sql' from /usr/local/lib/ruby/gems/1.8/gems/activerecord-1.15.2/lib/active_record/base.rb:1164:in add_conditions!’
from
/usr/local/lib/ruby/gems/1.8/gems/activerecord-1.15.2/lib/active_record/base.rb:1097:in
construct_finder_sql' from /usr/local/lib/ruby/gems/1.8/gems/activerecord-1.15.2/lib/active_record/base.rb:997:in find_every’
from
/usr/local/lib/ruby/gems/1.8/gems/activerecord-1.15.2/lib/active_record/base.rb:418:in
`find’
from (irb):2

Can anyone help?

Thanks
Ed

–
Ed Howland

2

Hi Ed,

Ed Howland wrote:

Student.find(:all, :conditions => { :grade => 9…12 })

but when I try this:

Customer.find :all, :conditions => [:id => 1…2]

I get:

NoMethodError: undefined method `%’ for {:id=>1…2}:Hash

I think your problem is in the use of [] instead of {} as in Jamis’
blog.

hth,
Bill

3

On 4/13/07, Bill W. [email protected] wrote:

Hi Ed,

Ed Howland wrote:
I think your problem is in the use of [] instead of {} as in Jamis’ blog.

hth,
Bill

Duh!
Thanks, Bill.

That was it. I guess I was just so used to using [] for the conditions
value.

Ed

Ed Howland

4

you could also do

Customer.find((1…2).to_a)

which is shorter in code, but could possibly cause problems if you
have a large range

Customer.find((1…2).to_a)
SELECT * FROM stories WHERE (stories.“id” IN (1,2,3,4,5))

Customer.find(:all, :conditions => { :id => (1…2) })
SELECT * FROM stories WHERE (stories.“id” BETWEEN 1 AND 5)

5

On 4/14/07, Chris H. [email protected] wrote:

Customer.find(:all, :conditions => { :id => (1…2) })
SELECT * FROM stories WHERE (stories.“id” BETWEEN 1 AND 5)

Chris,

Thanks, but I am actually trying to use this for Date ranges.

(Time.local(2007, 3, 1)…Time.local(2007, 4, 1)).to_a takes a REALLY
LONG TIME to complete. Probably because it is generating every second?

I have another question. Given :
:conditions => {:created_on => Time.local(2007, 3, 1)…Time.local(2007,
4, 1)}

how can I combine this with other conditions in the query? Normally, I
can manipulate the elements of the array (append " and " + new clause
to conditions[0] and append new value to conditions). But given that I
must supply a hash here to #find, I don’t see how to combine any other
conditions.

Ed

–
Ed Howland