[QUIZ] Pangrams (#86)

I let it run overnight in two irb sessions (with two different starter
sentences) and they both finally converged - but I don’t know how long
it
took.
Looking at the other solutions, I think I have plenty to learn about
Ruby -
especially when to modify an existing class, such as Integer or FixNum,
and
when to just do it in the domain-specific class. Everything here is in
the
domain-specific class but could be simpler in others.

iteration 2860162:
My sentence contains three 'a’s, one ‘b’, three 'c’s, two 'd’s, thirty
'e’s,
five 'f’s, four 'g’s, eight 'h’s, nine 'i’s, one ‘j’, one ‘k’,
one ‘l’, two 'm’s, twenty-one 'n’s, seventeen 'o’s, one ‘p’, one ‘q’,
eight
'r’s, twenty-four 's’s, twenty-two 't’s, four 'u’s, three 'v’s,
eight 'w’s, two 'x’s, six 'y’s and one ‘z’.

iteration 3224814:
John’s cool pangram program created this sentence which contains
exactly
eight 'a’s, one ‘b’, seven 'c’s, three 'd’s, forty-one 'e’s, eight
'f’s, five 'g’s, thirteen 'h’s, twelve 'i’s, two 'j’s, one ‘k’, four
'l’s,
three 'm’s, twenty-two 'n’s, seventeen 'o’s, three 'p’s, one ‘q’
, fifteen 'r’s, thirty-three 's’s, twenty-six 't’s, four 'u’s, seven
'v’s,
seven 'w’s, four 'x’s, six 'y’s and one ‘z’.

I haven’t tried a French version yet but it would likely work…

#===============================================================
require ‘Win32API’ # for checking the keyboard to stop and show the
progress

EXAMPLE_SENTENCE = “Darren’s ruby panagram program found this sentence
which
contains exactly
nine 'a’s, two 'b’s, five 'c’s, four 'd’s, thirty-five 'e’s, nine
'f’s,
three 'g’s, nine 'h’s, sixteen 'i’s, one ‘j’, one ‘k’, two 'l’s,
three 'm’s,
twenty-seven 'n’s, fourteen 'o’s, three 'p’s, one ‘q’, fifteen
'r’s,
thirty-four 's’s, twenty-two 't’s, six 'u’s, six 'v’s, seven
'w’s,
six 'x’s,
seven 'y’s, and one ‘z’.”

class Pangram
DEFAULT_SENTENCE = “John’s cool pangram program created this sentence
which contains exactly”
ENGLISH_NUMBERS = %w[? one two three four five six seven eight nine
ten
eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen
nineteen
twenty]
ENGLISH_THIRTY_PLUS = %w[thirty forty fifty sixty seventy eighty
ninety]
#this isn’t quite right for french: 21 and 31 and 41 are “thirty and
one”…
FRENCH_NUMBERS = %w[? un deux trois quatre cinq six sept huit neuf dix
onze douze treize quatorze quinze seize dix-sept dix-huit dix-neuf
vingt]
FRENCH_THIRTY_PLUS = %w[trente quarante cinquante soixante
soixante-dix
quatre-vingt quatre-vingt-dix]
MAX_COUNT = 50

attr_accessor :sentence

expect args to be [sentence,number_words,thirty_plus]

def initialize *args
@attempts = Hash.new(nil)
@sentence = args[0] || DEFAULT_SENTENCE
@words = args[1] || ENGLISH_NUMBERS
@words = @words.dup
@thirty_plus = args[1] || ENGLISH_THIRTY_PLUS
count = 30
@thirty_plus.each do |word|
@words[count] = word
count += 10
end

extend_wordlist MAX_COUNT
#puts "@sentence=#{@sentence}"
# only add one the first time, all the others already have the extra 

one

@result = letter_frequency @sentence
@result.each { |k,v| @result[k] += 1 }
#puts full_sentence( @result )
self

end

def distance hash1, hash2
dist = 0
hash1.each { |k,v| dist += (v - hash2[k]).abs }
return dist
end

def approximate current, start
# apply each letter-word to an empty list
approximation = {}
“a”.upto(“z”) { |c| approximation[c] = start }
current.each do |k,v|
@words[current[k]].split(’’).each do |c|
approximation[c] += 1 if approximation[c] and approximation[c]

= 0
end
end
return approximation
end

def unique_solution sentence,count
#puts “#{count}: crypt=#{crypt} for #{sentence}”
if @attempts[sentence] != nil
puts “Oops, we’ve already tried this solution! (#{count} ==>
#{@attempts[sentence]})”
return nil
else
@attempts[sentence] = count
return 1
end
end

def make_randomly_similar! dest, src
diffs = “”
dest.each { |k,v| diffs += k if v != src[k] }
c = diffs[ (rand * diffs.length).to_i ].chr
dest[c] = src[c]
end

def solve
iteration = 0
hash = {}
s = full_sentence( @result )
hash = letter_frequency( s )
w = Win32API.new( “MSVCRT”, “_kbhit”, [], ‘i’)
io = IO.new(0)
while hash != @result ## and unique_solution(s,iteration) != nil
iteration += 1
dist = distance( hash, @result )
puts “#{iteration}: #{dist}”
c = make_randomly_similar! @result, hash
#puts “iteration #{iteration}: #{dist},#{c} ==>
#{hash.sort.collect{|i| i[1] }.join(’,’) }”
s = full_sentence( @result )
hash = letter_frequency( s )
if w.Call() > 0
io.getc
puts “iteration #{iteration}: #{dist} ==> #{hash.sort.collect
{|i|
“#{i[0]}>#{i[1]}” }.join(’,’) }”
puts s
end
end
puts “\nSOLVED!\n #{s}”
puts “iteration #{iteration}: #{dist} ==> #{hash.sort.collect {|i|
i[1]
}.join(’,’) }”
show_freq letter_frequency(s)
end

def full_sentence hash
s = @sentence.rstrip + " "
“a”.upto(“x”) do |letter|
s += to_letter_count( letter, hash[letter] ) + ", "
end
s += to_letter_count( “y”, hash[“y”] ) + " and "
s += to_letter_count( “z”, hash[“z”] ) + “.”
return s
end

def to_letter_count letter, count
ret = “#{@words[count]} ‘#{letter}’”
ret += “s” if count > 1
return ret
end

def extend_wordlist count
0.upto(count) do |n|
@words[n] = @words[10*(n/10).floor] + ‘-’ + @words[n % 10] unless
@words[n]
#puts “#{n}: #{@words[n]}”
end
end

def show_freq hash
hash.sort.each { |k, v| puts “#{k}: #{v}” }
end

def letter_frequency *sentence
s = sentence[0] || @sentence
s = s.downcase.gsub(/^a-z/,’’)
s.gsub!(/ |,|’|-|./,’’)
freq = Hash.new(0)
“a”.upto(“z”) { |c| freq[c] = 0 }
s.split(’’).each { |c| freq[c] += 1 }
freq
end
end

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