Questions about Date.strptime

Hi all,

I want to parse some strings into Date object and I find in rdoc that
strptime is the right place to go. For some formats of string it’s
really easy to parse it. For instance, ‘%Y.%m.%d’ will parse something
like ‘2007.09.12’. But I have two kinds of string that I don’t now how
to parse.

‘20070912’: there is no ‘.’, ‘-’ or ‘/’ as the seperator and ‘%Y%m%d’
doesn’t work, it will throw an exception saying that: “ArgumentError: 3
elements of civil date are necessary”.

‘2007.09’: in this kind of string, I don’t care about the exactly
date(in fact, the data I received is lacked of that information). As a
result, ‘%Y.%m’ doesn’t work with the same error as above.

How can I deal with this two kinds of string? Thanks a lot.

Allen Young wrote:

strptime is the right place to go. For some formats of string it’s […]

‘20070912’: there is no ‘.’, ‘-’ or ‘/’ as the seperator and ‘%Y%m%d’
doesn’t work, it will throw an exception saying that: “ArgumentError: 3
elements of civil date are necessary”.

looks like it would be handy if there is something like

Date.strptime(“010207”, “%2m%2d%2y”).to_s

but right now that won’t run. maybe it tries to avoid ambiguity.

you can at least use one of these:

a = “20070923”

if match = /^(\d{4})(\d{2})(\d{2}$)/.match(a)
a.replace(match[1…3].join("/"))
puts a
end

a = “20070923”
a[4,0] = a[6,0] = “/”
puts a

E:>ruby date.rb
2007/09/23
2007/09/23

Allen Young wrote:

‘20070912’: there is no ‘.’, ‘-’ or ‘/’ as the seperator and ‘%Y%m%d’
doesn’t work, it will throw an exception saying that: “ArgumentError: 3
elements of civil date are necessary”.

‘2007.09’: in this kind of string, I don’t care about the exactly
date(in fact, the data I received is lacked of that information). As a
result, ‘%Y.%m’ doesn’t work with the same error as above.

How can I deal with this two kinds of string? Thanks a lot.

Try this:

require “parsedate”
include ParseDate

str = ‘20071029’
arr = parsedate(str)
p arr #[2007, 10, 29, nil, nil …]

begin
d = Date.new(arr[0], arg[1], arr[2])
puts d.year #2007
puts d.month #10
rescue ArgumentError
puts “invalid date, eg. month = 15”
end

str = ‘2007.9’
arr = parsedate(str)
p arr #[nil, 20, 7, nil, nil …]

pieces = str.split(".")
begin
d = Date.new(Integer(pieces[0]), Integer(pieces[1]), 1)
puts d.year #2007
puts d.month #9
rescue ArgumentError
puts “invalid date, e.g. day = 32”
end

7stud – wrote:

rescue ArgumentError
puts “invalid date, e.g. day = 32”
end

Actually, that ArgumentError could be caused by both the Integer() and
the Date.new() methods, so if you want to distinguish between the two
errors, you should convert to an Integer() in a different begin/rescue
block.

7stud – wrote:

Try this:

Whoops. I forgot to post a solution for that leading “0” in the month:

require “date”

str = ‘2007.09’

pieces = str.split(".")
begin
year = Integer(pieces[0])

month = pieces[1]
if month[0, 1] == '0'
    month = Integer(month[1,1])
else
    month = Integer(month)
end

rescue ArgumentError
puts “invalid date string: couldn’t convert to ints”
end

begin
d = Date.new(year, month, 1)
puts d.year
puts d.month
rescue ArgumentError
puts “invalid date args, e.g. day = 32”
end

7stud – wrote:

Whoops. I forgot to post a solution for that leading “0” in the month:

Here are some better ways:

month = “09”
begin
month = month.to_i(10)
puts month #9

raise ArgumentError if month == 0

rescue ArgumentError
puts “invalid date string”
end

#------------

require “scanf”

str = “2007.09”
year, month = str.scanf("%d.%d")
puts year #2007
puts month #9

str = “20080627”
y, m, d = str.scanf("%4d%2d%2d")
puts y, m, d #2008 6 27

At 4:08 PM +0900 9/23/07, Allen Young wrote:

elements of civil date are necessary".

‘2007.09’: in this kind of string, I don’t care about the exactly
date(in fact, the data I received is lacked of that information). As a
result, ‘%Y.%m’ doesn’t work with the same error as above.

How can I deal with this two kinds of string? Thanks a lot.

Hi Allen,

It surprises me that this isn’t easier. Here’s what I’m doing to
convert a similar input date/time format.

s = “20070926.155656”
d, t = s.scan(/\d+/) # => [“20070926”, “155656”]
d1 = “#{d[0…3]}-#{d[4…5]}-#{d[6…7]}” # => “2007-09-26”
t1 = “#{t[0…1]}:#{t[2…3]}:#{t[4…5]}” # => “15:56:56”
dt = “-#{d1}T#{t1}Z” # => “-2007-09-26T15:56:56Z”
dt1 = DateTime.parse(dt) # => #<DateTime:
10673317777/10800,0,2299161>

SpringFlowers AutumnMoon wrote:> a = “20070923”

if match = /^(\d{4})(\d{2})(\d{2}$)/.match(a)
a.replace(match[1…3].join("/"))
puts a
end

oops, or it can be

a = “20070923”
=> “20070923”

a.sub!(/^(\d{4})(\d{2})(\d{2})$/, ‘\1/\2/\3’)
=> “2007/09/23”

and then use Date.strptime

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