Problem replacing newlines in regexp

I’m trying to do a gsub ( “\n” , " " ) but none of the newlines are
replaced. Is there something special I have to do for newlines? (If it
makes
a difference, I’m running under Windows.)

Thanks,
Mike S.

On 4/30/07, Mike S. [email protected] wrote:

I’m trying to do a gsub ( “\n” , " " ) but none of the newlines are
replaced. Is there something special I have to do for newlines? (If it makes
a difference, I’m running under Windows.)

Try gsub!( “\n” , " " )

Harry

Harry wrote:

Harry

You’ve probably gotta specify the multiline match option (the /m at the
end):
line.gsub!(/\n/m, " ")

Dan

Okay, here’s the birds-eye view:

I’m converting some database data from pure text to CSV format, and I
need
to replace the newlines with something else (a space or a slash).

Sample input record:

Field1=value1
Field2=value2
more stuff in Field2
---------- # end-of-record separator

Sample output record:

FIELD1,FIELD2
value1,value2 / more stuff in Field2

Does that help?

And the /m option only changes how “.” is treated in a regexp, right?

Can I use somestring.gsub ( /$/ , " " ) instead of somestring.gsub (
/\n/ ,
" " )?

On 4/30/07, Dan Z. [email protected] wrote:

Harry

You’ve probably gotta specify the multiline match option (the /m at the
end):
line.gsub!(/\n/m, " ")

Dan

I just noticed the subject said regexp, not string. oops.
Mike, would you post some code?
It will make it easier to understand what you are trying to do.

Harry

Mike S. wrote:

---------- # end-of-record separator

Can I use somestring.gsub ( /$/ , " " ) instead of somestring.gsub ( /\n/ ,
" " )?

I guess you’re right that /m isn’t useful here. But gsub(/\n/, " ") does
seem to do what you want. And you can’t use /$/ here because when you
try to substitute for $, it doesn’t actually replace the end of the
line, but adds to it (so what you wrote adds a space to the end of each
line).

Dan

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