Print Layout

Rails
1

Hello All,

We have developed the following code in application.rb

def determine_layout
if !params[:layout].blank? and params[:layout] == “print”
@layout = “print”
else
@layout = “public”
@layout = “admin” if params[:controller] =~ /admin/
end
return @layout
end

This code allows us to use link with param in URL “layout=print”, so
the user can preview any page in browser without the menu, header,
footer and etc,

in this project we have only 2 layouts, but there are project where we
have 30 - 40 layouts,
does anybody know how to write this function in best way like

def determine_layout
if !params[:layout].blank? and params[:layout] == “print”
@layout = “print”
else
*** by default in controllers ***
end
return @layout
end

Regards,
Pavel

2

Hi Pavel,

se_pavel wrote:

This code allows us to use link with param in URL
“layout=print”, so the user can preview any page in
browser without the menu, header, footer and etc,

The easiest way of doing this is with CSS. You have a separate
stylesheet
for print media with the items you don’t want displayed set to ‘display:
none;’.

HTH,
Bill