Hello everybody,
Ruby is my first prgramming lenguage. I know it’s a simple question so
I hope someone can help me out. I have a file that i need to read,
here’s my code so far:
class Parser
File.open(“Data”) do |file|
while line = file.gets
end
end
end
somewhere in my file there is a table of strings like this:
“Hello” = “hi miguel”
“wrong” = “this is not the right anser”
“correct asnwer” = “this is the right asnwer”
“for what” = “tell me what you need it for”
My problem is this:
I want o search for this table, and read in such a way so that when I
call for a value(example, hello I can get its value, which is ‘hi
miguel’).
I know it’s a straigt forward process. I’m not sure how to search for
the table, and wheather to use a hash or arrays. Can anyone help me
out?
Thank you so much.
Ricardo
On Jul 19, 2006, at 4:47 PM, Ricardo F. wrote:
while line = file.gets
I know it’s a straigt forward process. I’m not sure how to search for
the table, and wheather to use a hash or arrays. Can anyone help me
out?
Thank you so much.
Ricardo
I find that each_line is nicer to work with than .gets for these
purposes. It would look like this:
File.open(“Data”) do |file|
file.each_line do |line|
#here pull the line appart (regular expressions are a good
choice, or maybe using the String#split function. Check ‘ri’ for that)
#Use the pulled apart piece to create a data structure
end
end
I’ll leave the middle parts to you. Be warned that the “line”
variable will still have a new line ("\n") at the end. A mistake
which caught me when I was first learning Ruby.
Good luck!
Mat
William J. wrote:
Ricardo F. wrote:
“Hello” = “hi miguel”
the table, and wheather to use a hash or arrays. Can anyone help me
out?
table = {}
IO.foreach(‘Data’) { |line|
if line =~ /^ \s* " (.?) " \s = \s* " (.*?) "/x
table[ $1 ] = $2
end
}
puts table[ “wrong” ]
Thanks for the help William,
I tried the code you wrote, but I got a nil as a result…I modified the
code as follows:
table = {}
IO.foreach(‘Localizable.strings’){ |line|
if line =~ /^ \s* " (.?) " \s = \s* " (.?) "\s/
table[ $1 ] = $2
end
}
am I missing something?
Hi –
On Thu, 20 Jul 2006, Ricardo F. wrote:
table[ $1 ] = $2
table = {}
IO.foreach(‘Localizable.strings’){ |line|
if line =~ /^ \s* " (.?) " \s = \s* " (.?) "\s/
table[ $1 ] = $2
end
}
am I missing something?
The /x modifier on the end of William’s regex means that literal
whitespace is ignored. (I’m a big non-fan of /x – I find it hard to
read regular expressions with a lot of insignificant whitespace mixed
in – but it has a following 
Without it, the regex engine will
look for actual spaces around the various quotation marks.
David
Ricardo F. wrote:
“Hello” = “hi miguel”
the table, and wheather to use a hash or arrays. Can anyone help me
out?
table = {}
IO.foreach(‘Data’) { |line|
if line =~ /^ \s* " (.?) " \s = \s* " (.*?) "/x
table[ $1 ] = $2
end
}
puts table[ “wrong” ]
Ricardo F. wrote:
table[ $1 ] = $2
table = {}
IO.foreach(‘Localizable.strings’){ |line|
if line =~ /^ \s* " (.?) " \s = \s* " (.?) "\s/
Removing the x is like removing the lead from your
mechanical pencil.
table[ $1 ] = $2
end
}
am I missing something?
–
Posted via http://www.ruby-forum.com/.
table = {}
Assumes that the filename is “Data”.
IO.foreach(‘Data’) { |line|
if line =~
# Regular expressions contain extremely condensed code.
# Therefore, anyone who has good sense knows that it is
# usually a good idea to use the x modifier which allows one
# to include whitespace and comments. A quote from
# Perl’s creator:
# Since /x extended syntax is now the default, # is
# now always a metacharacter indicating a comment,
# and whitespace is now always “meta”.
/
^ # Start of the string.
\s* # Optional whitespace (spaces or tabs).
" # A double quote.
(.?) # Capture the key in $1. The ? makes it non-greedy.
" \s # Double quote followed by optional whitespace.
= \s* # Equal sign followed by optional whitespace.
"
(.*?) # Capture value in $2.
"
/x # x for extended regular expression.
table[ $1 ] = $2
end
}
puts table[ “wrong” ]
p table