Operator precedence of assignment


#1

How do you think ruby parses this expression?
a = 1 + b = 2 + c = 4 + d = 8

Originally I thought that operator precedence would result in
a = (1 + b) = (2 + c) = (4 + d) = 8
and since an assignment requires a variable, that would result in a
SyntaxError.
But instead it seems that everything on the right side of the assignment
operator is evaluated first:
a = (1 + (b = (2 + (c = (4 + (d = 8))))))

That had me really puzzled at first but I guess the behavior makes a
certain
sense, and it’s more useful than a syntax error. Ruby’s tolerant parser
wins again!

Daniel


#2

Daniel DeLorme wrote:

How do you think ruby parses this expression?
a = 1 + b = 2 + c = 4 + d = 8

Per…
http://phrogz.net/ProgrammingRuby/language.html#operatorexpressions
…the + operator has much higher precedence than the assignment
operator. That’s interesting that it doesn’t parse as you expected.
It’s what I would have expected, too.


#3

Hi,

In message “Re: operator precedence of assignment”
on Tue, 2 Jan 2007 22:26:53 +0900, Daniel DeLorme removed_email_address@domain.invalid
writes:
|
|How do you think ruby parses this expression?
| a = 1 + b = 2 + c = 4 + d = 8
|
|Originally I thought that operator precedence would result in
| a = (1 + b) = (2 + c) = (4 + d) = 8
|and since an assignment requires a variable, that would result in a SyntaxError.
|But instead it seems that everything on the right side of the assignment
|operator is evaluated first:
| a = (1 + (b = (2 + (c = (4 + (d = 8))))))
|
|That had me really puzzled at first but I guess the behavior makes a certain
|sense, and it’s more useful than a syntax error. Ruby’s tolerant parser wins again!

Ah, for your information, that surprised me as well. Perhaps bison
generated parser is smarter and eagerer than I expected. I have no
idea what to do.

						matz.

#4

On 02.01.2007 17:56, Yukihiro M. wrote:

|and since an assignment requires a variable, that would result in a SyntaxError.
|But instead it seems that everything on the right side of the assignment
|operator is evaluated first:
| a = (1 + (b = (2 + (c = (4 + (d = 8))))))
|
|That had me really puzzled at first but I guess the behavior makes a certain
|sense, and it’s more useful than a syntax error. Ruby’s tolerant parser wins again!

Ah, for your information, that surprised me as well. Perhaps bison
generated parser is smarter and eagerer than I expected. I have no
idea what to do.

I think Daniel did not want you to do anything - in fact he seems rather
positively amazed. :slight_smile:

(The only thing that comes to mind is thank him for the praise. :-))

Kind regards

robert

#5

On 02.01.2007 18:09, Yukihiro M. wrote:

|(The only thing that comes to mind is thank him for the praise. :-))

The praise should go to yacc, not me. :wink:

But you chose it, didn’t you? So… :slight_smile:

robert

#6

Hi,

In message “Re: operator precedence of assignment”
on Wed, 3 Jan 2007 02:05:06 +0900, Robert K.
removed_email_address@domain.invalid writes:

|I think Daniel did not want you to do anything - in fact he seems rather
|positively amazed. :slight_smile:

That made me wonder what I should do.

|(The only thing that comes to mind is thank him for the praise. :-))

The praise should go to yacc, not me. :wink:

						matz.