Hi,
Can some one please tell me of an example expression which maps to this
regex
“(^#{r}$)”
The ruby statement is
regex = Regexp.new("(^#{r}$)")
Hi,
Can some one please tell me of an example expression which maps to this
regex
“(^#{r}$)”
The ruby statement is
regex = Regexp.new("(^#{r}$)")
r = ‘hello’
str = ‘hello’
if Regexp.new(“(^#{r}$)”).match str
puts “Yep”
puts $1
end
–output:–
Yep
hello
Try practicing here:
7stud – wrote in post #1081740:
r = ‘hello’
str = ‘hello’if Regexp.new("(^#{r}$)").match str
puts “Yep”
puts $1
end–output:–
Yep
hello
Thanks for the prompt reply. Can you explain a bit about #{r}. What that
means ??
greeting = ‘hello’
str = “#{greeting} world”
puts str
–output:–
hello world
It’s called ‘string interpolation’. It’s used to insert the value of a
variable (or an expression) into a string.
On Oct 28, 2012, at 18:14 , Muhammad S. [email protected]
wrote:
Hi,
Can some one please tell me of an example expression which maps to this
regex“(^#{r}$)”
The ruby statement is
regex = Regexp.new(“(^#{r}$)”)
it is entirely dependent on what r
evaluates to… so no, we can’t
really.
Hi Muhammad,
That depends entirely on what the value of “r” is. The #{} is
interpolation, like in strings.
e.g.
r = /boo/
regexp = Regexp.new("(^#{r}$)")
regexp is now /(^(?-mix:boo)$)/, which is basically the same as saying
/(^(?:boo)$)/, … which is basically the same as /(^boo$)/ in this
context.
In other words, the value of “r” gets included there, with any options
on the regexp “r” set. If “r” is a String, its value is included
verbatim, as if it was part of the regexp source.
Cheers,
Arlen
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