Hi,
Thanks for all the fantastic work that has gone into ruby. Even
though I am new it has proved to be very impressive.
To my question.
I’ve seen the following code:
@vara, @varb = “ab,ac,ad,ae”.split(",")
the way @vara and @varb were used makes me think the writer expected
the following:
puts @vara.inspect # “ab”
puts @varb.inspect # [“ac”, “ad”, “ae”]
However when I run this code I get
puts @vara.inspect # “ab”
puts @varb.inspect # “ac”
Is there a way to achieve the writer seemed to have in mind?
Thanks in advance
Mark
Hi –
On Wed, 9 May 2007, Mark V wrote:
puts @vara.inspect # “ab”
puts @varb.inspect # [“ac”, “ad”, “ae”]
However when I run this code I get
puts @vara.inspect # “ab”
puts @varb.inspect # “ac”
Is there a way to achieve the writer seemed to have in mind?
Yes:
@vara, *@varb = “ab,ac,ad,ae”.split(",")
David
On May 9, 2007, at 6:41 AM, Mark V wrote:
puts @vara.inspect # “ab”
puts @varb.inspect # [“ac”, “ad”, “ae”]
@vara, *@varb = “ab,ac,ad,ae”.split(",")
The asterisk (or ‘splat’) operator is the key.
Gary W.
Thank you David and Gary!
Regards
Mark
On Wed, May 09, 2007 at 07:41:05PM +0900, Mark V wrote:
However when I run this code I get
puts @vara.inspect # “ab”
puts @varb.inspect # “ac”
Is there a way to achieve the writer seemed to have in mind?
@vara, *@varb = “ab,ac,ad,ae”.split(",")