Need some help with regexp

Ruby
1

Hello, I need some help with regex
I have the following expression: “Laptop MARCOCHEN (192.168.5.73)”
I need a regular express to capture only the second word, in this case
“MARCOCHEN”. I don’t want to use “split”

So far I am using / \S+ /i
but this is getting also the spaces before and after so what I am
getting is " MARCOCHEN "

Any advice?

Thanks a lot!

2

You are getting that because you have spaces in it. You can get the same
result if you use /(\S+)/ and using the $1 variable, which should
contain
“MARCOCHEN”.

On Sun, Oct 2, 2011 at 11:46 AM, Eyal Eizenberg
<[email protected]

wrote:

Thanks a lot!

–
Posted via http://www.ruby-forum.com/.

–
Sincerely,

Isaac S.
Section C-4B Vice Chief, Order of the Arrow
Vice Chief of Administration, Tecumseh #65
Eagle Scout

3

Is there a way to do it so that the $& will contain “MARCOCHEN”?

Isaac S. wrote in post #1024664:

You are getting that because you have spaces in it. You can get the same
result if you use /(\S+)/ and using the $1 variable, which should
contain
“MARCOCHEN”.

4

Eyal Eizenberg wrote in post #1024722:

Is there a way to do it so that the $& will contain “MARCOCHEN”?

Base on your pattern, /(?<= )\S+(?= )/i will work.

5

On Mon, Oct 3, 2011 at 9:06 AM, Eyal Eizenberg
[email protected] wrote:

Is there a way to do it so that the $& will contain “MARCOCHEN”?

Isaac S. wrote in post #1024664:

You are getting that because you have spaces in it. You can get the same
result if you use /(\S+)/ and using the $1 variable, which should
contain
“MARCOCHEN”.

Even better - you don’t need $&:

irb(main):001:0> s=“Laptop MARCOCHEN (192.168.5.73)”
=> “Laptop MARCOCHEN (192.168.5.73)”
irb(main):002:0> s[/\A\s*\w+\s+(\w+)/, 1]
=> “MARCOCHEN”

or

irb(main):005:0> s[/\A\s*\S+\s+(\w+)/, 1]
=> “MARCOCHEN”

Kind regards

robert

6

$~ has the matched result from the most recent regexp. Convert to a
string thusly

($~).to_s

Joe

Sent from my iPad

7

Please do not top post.

On Mon, Oct 3, 2011 at 6:42 PM, [email protected]
[email protected] wrote:

$~ has the matched result from the most recent regexp. Convert to a string
thusly

($~).to_s

You’re point being? Why would I bother to use $~.to_s if I can
directly use $& and get the same? Also, my point was specifically
that you can get away without those global variables and instead use
what String#[] returns.

Joe

Sent from my iPad

Maybe you had better used a real computer.

Cheers

robert

8

$& works fine also

Joe

Sent from my iPad

9

I have a real computer but not always access to it

Joe

Sent from my iPad