Need help with $end vs kEND error

Ruby
1

I have been trying to write a program for my class assignment but
everytime i do i get an error on the last line of the code that says
‘unexpected $end, expecting kEND’
this happens on every program i try to run
any ideas?

i am using fedora core 5 if that makes a difference

2

Kd Kushelduv wrote:

I have been trying to write a program for my class assignment but
everytime i do i get an error on the last line of the code that says
‘unexpected $end, expecting kEND’
this happens on every program i try to run
any ideas?

i am using fedora core 5 if that makes a difference

Often times this error is a result of missing an end statement somewhere
within your program. For example, you may have forgotten to end a
method, if statement or class. Can you post some code so we can take a
look?

3

You have mismatched block openings / endings. Check your def / end
do / end if / end, etc…

4

I’m just learning ruby myself, but typically when this
happens, I’m missing an end to a function, or some other
block:

#!/usr/bin/ruby

def joe
print “JOE MAMMA\n”

Produces:

[alibby@localhost ~]$ ./t.rb
./t.rb:6: syntax error, unexpected $end, expecting kEND

Perhaps this is it? If you’re willing to post the code (if
it’s not too long) we may be able to provide more guidance.

Andy

5

as far as i can tell nothing is missing
here is the code (its only three methods):

def promptToQuit
print "\nYou did not enter any numbers \n are you sure you wish to
quit? (y/n): "
answer = getc
answer = answer.downcase
while (answer != ‘y’ && answer != ‘n’)
print "Are you sure you wish to quit? (y/n): "
answer = getc
answer = answer.downcase
end

return answer
end

def getNumbers (num)
$high = num
$low = num

while (num != 0)
print "Please enter a number (0 to quit): "
num = geti

  if ( (num > $high) && (num != 0) ) then
     $high = num
  else if ( (num < $low) && (num != 0) ) then
     $low = num
  end

end
end

answer = ‘n’

print "\nPlease enter a number (0 to quit): "
num = geti

if (num == 0) then
answer = promptToQuit
end

if (answer == ‘y’) then
print “\nGoodbye”
else
num = 1
getNumbers(num)
end

puts "Highest Number: " + $high.to_s
puts "Lowest Number: " + $low.to_s
puts “\n”

6

huh that was the problem but my text book had everything as
elseif

i added the space because it wouldn’t accept that
but it seems the author still mistyped the entire thing

o well

7

Kd Kushelduv wrote:

  if ( (num > $high) && (num != 0) ) then
     $high = num
  else if ( (num < $low) && (num != 0) ) then
     $low = num
  end

This should be

   if ( (num > $high) && (num != 0) ) then
      $high = num
   elsif ( (num < $low) && (num != 0) ) then
      $low = num
   end

Your else is starting a new block context (not the Ruby term I’m sure;
that’s kinda what I’d call it in Perl :slight_smile: and Ruby thinks what you’re
doing is:

if …

else
if …
end
end

But you’ve only got a single end so it’s confuzzled.

8

Kd Kushelduv wrote:

huh that was the problem but my text book had everything as
elseif

i added the space because it wouldn’t accept that
but it seems the author still mistyped the entire thing

Umm, just curious, who is the author, what is the book or article?

9

On 2006.10.11 03:23, Kd Kushelduv wrote:

  answer = getc

while (num != 0)
print "Please enter a number (0 to quit): "
num = geti

  if ( (num > $high) && (num != 0) ) then
     $high = num
  else if ( (num < $low) && (num != 0) ) then
     $low = num

Right here. You want elsif, otherwise you are missing
the closing end for the nested if. Also, drop the thens,
they are not needed :slight_smile:

answer = promptToQuit
puts "Lowest Number: " + $low.to_s
puts “\n”

The error message is a bit ambiguous–$end means EOF, which
Ruby encountered while it was still waiting for a literal
end (the token is called kEND).