I’m creating a meta script that can generate both a shell script and a
Makefile. I want the script to be human readable, so I don’t want to
substitute all the variables, so $(top_srcdir) =
“/my/obsenely/huge/directory/name” doesn’t get substituted in for
example $(srcdir) = $(top_srcdir)/foo.
The problem is that bash doesn’t use the same syntax for variable
substitution.
I guess the easiest thing to do is just s/$()/${}/ but I was wondering
if there’s a better way to do that.
Since I know Rubyists can always find better ways to write code I
decided to ask here.
Is there a better way to implement meta variable substitution?
I guess the easiest thing to do is just s/$()/${}/ but I was wondering
if there’s a better way to do that.
Since I know Rubyists can always find better ways to write code I
decided to ask here.
Is there a better way to implement meta variable substitution?
Are you parsing the files? I had the impression that you are
generating them. In that case I would just generate the variable names
rather late and somehow factorize
the code into
def var_name name
“${#{name}}”
end
def var_name name
“$(#{name})”
end
if this polymorphic approach is not suitable for your design an if
statement shall do.