May I know that why the zz[0]=="s" return false, please?

Dear Sir,

May I know that why the zz[0]==“s” return false, please?

aa = ‘“s”;“d”;“f”’
zz = aa.split(";")
zz[0]==“s”
false

Thanks

Regards
Oscar

On Aug 26, 2010, at 12:35 PM, Oscar L. wrote:

Dear Sir,

May I know that why the zz[0]==“s” return false, please?

aa = ‘“s”;“d”;“f”’
zz = aa.split(";")
zz[0]==“s”
false

“s” is a string containing one actual character (s). While you have 3
after split – double quote, s, double quote. So you need to check for
‘“s”’ instead:

zz[0] == ‘“s”’
true

On Thu, Aug 26, 2010 at 2:35 PM, Oscar L.
[email protected]wrote:

Regards
Oscar

Posted via http://www.ruby-forum.com/.

You output an inspected view of your objects with the method p, that
should
help you see the difference.

aa = ‘“s”;“d”;“f”’
zz = aa.split(";")
p zz[0]
p “s”

Because it is.

The original string which you split on results in “s” being assigned to
zz[0], including the quotes. (i.e. you’re assigning three characters to
each array element).

When you compare for equality on the next line, due to syntax you’re
only comparing to one character - s - as the quotes indicate to ruby
that it’s dealing w/ a string literal.

Try this:
zz[0] == ““s””

Thanks for all of you!!!

Regards
Oscar

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