Match doesn't match

arg1 = “(1)a”
arg2 = “(1)a”

if arg1.match(arg2)
puts “Matched”
else
puts “Don’t Matched”
end

gives me “Don’t Matched” ??

Regards,
Volkan

arg2 should be escaped as () has a meaning in regexps.

arg2 = “\(1\)a”

p “match” if arg1.match(arg2)

hth,

./alex

.w( the_mindstorm )p.

On 18-Jul-06, at 8:57 PM, Volkan Civelek wrote:

gives me “Don’t Matched” ??

That’s because parentheses are special in a pattern, and that’s what
the String#match expects as an argument. You can use Regexp.escape
to escape special characters:

mike$ irb --prompt simple

arg1 = “(1)a”
=> “(1)a”

arg2 = “(1)a”
=> “(1)a”

arg1.match(arg2)
=> nil

arg1.match(Regexp.escape(arg2))
=> #MatchData:0x34d6ac

Hope this helps,

Mike

Mike S. [email protected]
http://www.stok.ca/~mike/

The “`Stok’ disclaimers” apply.

Try it with

arg1 = “(1)a”
arg2 = ‘(1)a’

The problem is that arg2 is converted to a regular expression by
“match” and “(” and “)” are special characters in regular expressions
and, therefore, must be escaped.

Regards, Morton

arg2 should be escaped as () has a meaning in regexps.

arg2 = “\(1\)a”

p “match” if arg1.match(arg2)

Possibly, Volkan Civelek, you simply wanted to see if the two string
were equal? In that case you would do:

arg1 = “(1)a”
arg2 = “(1)a”

if arg1 == arg2
puts “Matched”
else
puts “Don’t Matched”
end

Cheers,
Benj

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