Is there any equivalent technique of Array#product?

Is there any equivalent technique of Array#product?

Can the same code be done in any other way?

[1,2,3].product([6,7])
#=> [[1, 6], [1, 7], [2, 6], [2, 7], [3, 6], [3, 7]]

Thanks in advance!

Yes. Why?

Adam P. wrote in post #1103670:

Yes. Why?

Out of curiosity.

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