I am trying to find an easier way to split a string into printable
lines. I could use the method of checking for a space using a loop and
going back from the desired length or I could use the following:
def strbrk(str, len)
if str.length <= len
return str.length
end
tmp = str[0…len].reverse
x = tmp =~ / /
if x == nil
return -1
else
return len - x
end
end
I could not find any way to get a regexp to search from the end of the
string which would have eliminated the need to reverse the string.
On Jan 22, 2008 5:14 AM, Michael W. Ryder [email protected]
wrote:
I could not find any way to get a regexp to search from the end of the
string which would have eliminated the need to reverse the string.
str.rindex(/ /, len) ?
On Jan 21, 1:12 pm, “Michael W. Ryder” [email protected]
wrote:
if x == nil
return -1
else
return len - x
end
end
I could not find any way to get a regexp to search from the end of the
string which would have eliminated the need to reverse the string.
This should work:
/ [^ ]*$/
It looks for one space, followed by 0 or more occurrences of anything
besides a space, followed by the end of the string.
On Jan 21, 1:12 pm, “Michael W. Ryder” [email protected]
wrote:
if x == nil
return -1
else
return len - x
end
end
I could not find any way to get a regexp to search from the end of the
string which would have eliminated the need to reverse the string.
def str_break( str, len )
str.size > len and str[0…len].rindex(’ ') or str.size
end
str = "
I don’t necessarily need code examples – but if anyone has
ideas for a best approach to specifying a line wrap width
(breaking between words for lines no longer than a specific
column width) for output from a Ruby script, I’d love to
hear about it."
X = 40
puts str.gsub(/\n/," ").scan(/\S.{0,#{X-2}}\S(?=\s|$)|\S+/)
William J. wrote:
…
str = "
I don’t necessarily need code examples – but if anyone has
ideas for a best approach to specifying a line wrap width
(breaking between words for lines no longer than a specific
column width) for output from a Ruby script, I’d love to
hear about it."
X = 40
puts str.gsub(/\n/," ").scan(/\S.{0,#{X-2}}\S(?=\s|$)|\S+/)
Kaspar S. wrote text-reform (gem install text-reform)
require ‘text/reform’
r = Text::Reform.new
while line=gets
puts r.format(‘[’*40, line)
end
Here he says it does hyphenate:
http://blog.macromates.com/2006/wrapping-text-with-regular-expressions/
William J. wrote:
tmp = str[0…len].reverse
def str_break( str, len )
str.size > len and str[0…len].rindex(’ ') or str.size
end
I did find one more “improvement” on your code after reading further on
rindex.
def str_break( str, len )
str.size > len and str.rindex(’ ', len) or str.size
end
It appears to work the same and give the same results but I am not sure
if there was a reason for the way you did it that I missed.
Thanks for the push in the right direction.
William J. wrote:
tmp = str[0…len].reverse
def str_break( str, len )
str.size > len and str[0…len].rindex(’ ') or str.size
end
This is much better than my solution, I missed rindex somehow.