Irb: 1 & 1 => 1, not true huh? I thought 1 & 1 => true

Ruby
1

In irb I did:

puts 1 & 1
and get 1
shouldn’t I get true?

Bottom line is this: What is Ruby idiom to test for bit mask? Is there
a more simple way to write:

if session[:permissions] & Permissions::SomeMask ==
Permissions::SomeMask

user has permission to wash clothes, etc.

end

TIA,
Pete

2

Peter A. wrote:

Permissions::SomeMask

user has permission to wash clothes, etc.

end

a && b returns the first false element or the last true element.

a & b where a and b are Fixnums does a bit mask like you’re looking for.

  • Charlie
3

On Sep 28, 4:19 pm, Peter A. [email protected] wrote:

Permissions::SomeMask

user has permission to wash clothes, etc.

end

TIA,

You say thanks when nobody has replied, so
you are thanking nobody. You should wait
till someone has replied before you thank
him. Otherwise, he won’t even know that you
have read his post; that is very rude and
inconsiderate.

Pete

bitwise

254 & 15
==>14

boolean

254 && 15
==>15

Only two things are untrue: nil and false.

puts “it’s true” if 0
it’s true
==>nil
puts “it’s true” if 254 & 1
it’s true
==>nil
puts “it’s true” if 254 & 1 > 0
==>nil

4

Bottom line is this: What is Ruby idiom to test for bit mask? Is there
a more simple way to write:

if session[:permissions] & Permissions::SomeMask ==
Permissions::SomeMask

user has permission to wash clothes, etc.

end

That’s basically right - you can factor this out into your own method if
you do it a lot.

If you want to test for a single bit, there is Fixnum#[]

a = 14
a[0] # 0
a[1] # 1
a[2] # 1
a[3] # 1
a[4] # 0

You’d still have to test for a[2] == 1, since 0 and 1 are both true.

However you could use a different representation for your permissions,
such as a string containing a single letter for each permission granted.
Then:

if session[:permissions].include?(“w”)
# user has permission to wash clothes
end

or simply

if session[:permissions][“w”]
# user has permission to wash clothes
end

5

Hi,

At Mon, 29 Sep 2008 06:19:01 +0900,
Peter A. wrote in [ruby-talk:316270]:

puts 1 & 1
and get 1
shouldn’t I get true?

No. If it were, bit AND operation would be unavailable.

if session[:permissions] & Permissions::SomeMask ==
Permissions::SomeMask

if (session[:permissions] & Permissions::SomeMask).nonzero?