Can anyone explain this?
a = [“b”]
=> [“b”]a == “b”
=> false“#{a}” == “b”
=> true
Since a is an array, how come the last statement evaluates as true?
Can anyone explain this?
a = [“b”]
=> [“b”]a == “b”
=> false“#{a}” == “b”
=> true
Since a is an array, how come the last statement evaluates as true?
François Montel wrote:
=> true
Since a is an array, how come the last statement evaluates as true?
“#{ [“b”] }” == [“b”].to_s #=> true
[“b”].to_s == “b” #=> true
[“b”].to_s #=> “b”
“#{a}” == “b”
=> true
Since a is an array, how come the last statement evaluates as true?
You could try ruby 1.9, if you prefer false:
a = [“b”]
=> [“b”]
“#{a}” == “b”
=> false
“#{a}”
=> “[“b”]”
[“b”].to_s
=> “[“b”]”
le 22/03/2009 14:53, François Montel nous a dit:
Can anyone explain this?
a = [“b”]
=> [“b”]a == “b”
=> false“#{a}” == “b”
=> trueSince a is an array, how come the last statement evaluates as true?
Because, since it’s embedded in a string Ruby does a .to_s against the
array. And [“b”].to_s == “b” is true
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