Can anyone explain this?

a = [“b”]

=> [“b”]a == “b”

=> false“#{a}” == “b”

=> true

Since a is an array, how come the last statement evaluates as true?

Can anyone explain this?

a = [“b”]

=> [“b”]a == “b”

=> false“#{a}” == “b”

=> true

Since a is an array, how come the last statement evaluates as true?

François Montel wrote:

=> true

Since a is an array, how come the last statement evaluates as true?

“#{ [“b”] }” == [“b”].to_s #=> true

[“b”].to_s == “b” #=> true

[“b”].to_s #=> “b”

“#{a}” == “b”

=> true

Since a is an array, how come the last statement evaluates as true?

You could try ruby 1.9, if you prefer false:

a = [“b”]

=> [“b”]

“#{a}” == “b”

=> false

“#{a}”

=> “[“b”]”

[“b”].to_s

=> “[“b”]”

le 22/03/2009 14:53, François Montel nous a dit:

Can anyone explain this?

a = [“b”]

=> [“b”]a == “b”

=> false“#{a}” == “b”

=> trueSince a is an array, how come the last statement evaluates as true?

Because, since it’s embedded in a string Ruby does a .to_s against the

array. And [“b”].to_s == “b” is true