Hello,
I have a ferret index with 2 fields:
Acts_as_ferret :fields => [:client, :content]
If I do model.find_by_contents(query) I obtain all results by the query
but I would like to obtain 3 results for each client.
Any ideas?
Thanks for all.
Hello,
I have a ferret index with 2 fields:
Acts_as_ferret :fields => [:client, :content]
If I do model.find_by_contents(query) I obtain all results by the query
but I would like to obtain 3 results for each client.
Any ideas?
Thanks for all.
Hi Ramon,
I think you’d have to do three different queries:
query = params[:query]
@results1 = model.find_by_contents(“client:1 content:#{query}”, {:limit
=>
3})
@results2 = model.find_by_contents(“client:2 content:#{query}”, {:limit
=>
3})
@results3 = model.find_by_contents(“client:3 content:#{query}”, {:limit
=>
3})
Ferret is fast enough that this shouldn’t be a performance problem.
Thanks,
Doug
Thanks Doug,
I thought that ferret could do this query. I don’t know to priory the
total of clients i have. If i have 100 clients, i can’t do it. Too, I
would like to use the pagination.
Ramón.
Doug S. wrote:
Hi Ramon,
I think you’d have to do three different queries:
query = params[:query]
@results1 = model.find_by_contents(“client:1 content:#{query}”, {:limit
=>
3})
@results2 = model.find_by_contents(“client:2 content:#{query}”, {:limit
=>
3})
@results3 = model.find_by_contents(“client:3 content:#{query}”, {:limit
=>
3})Ferret is fast enough that this shouldn’t be a performance problem.
Thanks,
Doug
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