How to round up a float number?


#1

for example:

i = 0.33533333333 round up to “0.34”

thanks.


#2

On Tue, 2007-01-16 at 03:54 -0800, Michael W. wrote:

david wrote:

i = 0.33533333333 round up to “0.34”

sprintf("%2.2f", i)

Hmm and if you want a float then:

eval(sprintf("%2.2f",i))

Also, if you want to just round:

i.round #=> will give 0 for 0.33335

And If you don’t really like eval then, you would have to get your hand
dirty and :

class Float
def round2f places
sprintf("%.#{places}f",self).to_f
end
end


#3

david wrote:

i = 0.33533333333 round up to “0.34”

sprintf("%2.2f", i)


Michael W.


#4

hi,
what about this…

irb(main):035:0> i = 0.33533333333
=> 0.33533333333
irb(main):036:0> Integer(i*100)/100.0
=> 0.33

in case .34 is required
can do
irb(main):040:0> Integer((i*100).ceil)
=> 34

regards
gaurav


#5

Hi, I’ve got it. thanks, everyone.

On 1 16 , 10 53 , “gaurav bagga”