length = 20
text = ’ This forum is connected to a mailing list that is read by
thousands of people.’
text.split[0…length]
I looked at the split api but can’t understand how the above code is
working.
length = 20
text = ’ This forum is connected to a mailing list that is read by
thousands of people.’
text.split[0…length]
I looked at the split api but can’t understand how the above code is
working.
Raj S. wrote:
length = 20
text = ’ This forum is connected to a mailing list that is read by
thousands of people.’text.split[0…length]
I looked at the split api but can’t understand how the above code is
working.
split() returns an array, and:
arr = [10, 20, 30, 40]
p arr
slice = arr[0…2]
p slice
–output:–
[10, 20, 30, 40]
[10, 20, 30]
Raj S. wrote:
length = 20
text = ’ This forum is connected to a mailing list that is read by
thousands of people.’text.split[0…length]
I looked at the split api but can’t understand how the above code is
working.
Its not specific how you want to split your string but may be
split_text = split(’’)
will split the string of characters like,
T
h
i
s
f
o
…
so samething like
split_text = split(’ ')
withh split the string into an array of strings like
This
forum
is
connected
to
a
mailing
list
…
so if you give your specifications clearly we are ready to help you Raj
singh…
— Jose Martin
From: Raj S. [mailto:[email protected]]
Hi Raj,
u didn’t show what you wanted.
so (i guess :), maybe you want string#[] or string#slice instead,
length=20
#=> 20
text = ’ This forum is connected to a mailing list that is read by
thousands of people’
#=> " This forum is connected to a mailing list that is read by
thousands of people"
text[0,length]
#=> " This forum is conne"
text[0…length-1]
#=> " This forum is conne"
text[length…-1]
#=> “cted to a mailing list that is read by thousands of people”
kind regards -botp
if you look at the comments of this blog
http://daniel.collectiveidea.com/blog/2007/7/10/a-prettier-truncate-helper
you will find following code.
def truncate_words(text, length = 10, separator = ’ ', truncate_string =
‘…’)
’ ’ if text.nil?
truncated_text = text.split[0…length].join(separator)
if(truncated_text == text)
text
else
truncated_text + ’ ’ + truncate_string
end
end
I had never seen text.split[0…length] before. What’s happening here. I
always saw split being passed an argument but never an array.
From: [email protected] [mailto:[email protected]]
an array was *never passed.
try playing w irb,
text
#=> " This forum is connected to a mailing list that is read by
thousands of people"
text.split
#=> [“This”, “forum”, “is”, “connected”, “to”, “a”, “mailing”, “list”,
“that”, “is”, “read”, “by”, “thousands”, “of”, “people”]
text.split[0…5]
#=> [“This”, “forum”, “is”, “connected”, “to”, “a”]
text.split[0…5].join " "
#=> “This forum is connected to a”
kind regards -botp
Peña, Botp wrote:
From: Raj S. [mailto:[email protected]]
length = 20
text = ’ This forum is connected to a mailing list that is read by
thousands of people.’
text.split[0…length]
I looked at the split api but can’t understand how the above code is
working.
Hi Raj,
u didn’t show what you wanted.
so (i guess :), maybe you want string#[] or string#slice instead,
length=20
#=> 20text = ’ This forum is connected to a mailing list that is read by
thousands of people’
#=> " This forum is connected to a mailing list that is read by
thousands of people"text[0,length]
#=> " This forum is conne"text[0…length-1]
#=> " This forum is conne"text[length…-1]
#=> “cted to a mailing list that is read by thousands of people”kind regards -botp
yes i agree with your comments.
raj you did not specified what you need clearly but hope the above would
help you a lot in your work.
this is the thing you expected?
ready to do it for you but need specifications clearly.
– jose martin
Raj S. wrote:
I had never seen text.split[0…length] before. What’s happening here. I
always saw split being passed an argument but never an array.
The code you originally posted:
result = text.split[0…length]
is equivalent to:
arr = text.split
result = arr[0…length]
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