Ok I know that sounds newbish, but I don’t want to match the entire
string. I just want to match the first 25 characters or so.
I have a hash that looks like
somestuff[:something]
Now I want somestuff[:something] to equal a string.
somestuff[:something] == ‘sadfasdfsdfasdf’
the problem is that somestuff[:something] will never match the entire
string, so I want to match the first 25 characters.
Any ideas…I hope that made sense?
On Mar 17, 2009, at 3:24 PM, Chris G. wrote:
somestuff[:something] == ‘sadfasdfsdfasdf’
the problem is that somestuff[:something] will never match the entire
string, so I want to match the first 25 characters.
Any ideas…I hope that made sense?
somestuff[:something][0,25] = “asdfasdfasdf”
Is one way. There’s probably a ruby method to match N characters of a
string similar to C’s strncmp too.
Chris G. wrote:
Ok I know that sounds newbish, but I don’t want to match the entire
string. I just want to match the first 25 characters or so.
I have a hash that looks like
somestuff[:something]
Now I want somestuff[:something] to equal a string.
somestuff[:something] == ‘sadfasdfsdfasdf’
the problem is that somestuff[:something] will never match the entire
string, so I want to match the first 25 characters.
Any ideas…I hope that made sense?
There are a number of ways depending on your needs. In your case if you
just want to match the beginning of the string Rails provides the
starts_with method (Ruby 1.9 provides start_with, but not Ruby 1.8). For
more complex matches Ruby has excellent regex support. Look at the ~=
method.
somestuff[:something].starts_with “whatever”
somestuff[:something] ~= /^whatever.+/i
Robert W. wrote:
just want to match the beginning of the string Rails provides the
starts_with method (Ruby 1.9 provides start_with, but not Ruby 1.8). For
more complex matches Ruby has excellent regex support. Look at the ~=
method.
somestuff[:something].starts_with “whatever”
Thanks for the info…
Can “whatever” be a variable?