How can I read byte by byte from a file and send it to input stream of a block


#1

Hi,
I want to read a byte from a file and send it to an input stream. Each
time
I read one byte from the file i want to send it onto the input stream of
a
particular block and then read the next byte and do the same. I looked
at
gr.message_source() which does similar work to what I need. But I see
that
when we use gr.message_from_string(databyte) and then do
msgq().insert_tail(msg) we add some more information to the data byte. I
just want to send the particular byte read onto the stream. How can I do
this?

Thanks
Ali


#2

On Mon, Dec 29, 2008 at 03:48:15AM -0600, Mir A. wrote:

Thanks
Ali

gr.file_source(gr.sizeof_char, “/path/to/my/file”)


#3

Hi Eric ,

I know what file_source does but I was looking for something else.
Please
look at the code below to know what i am looking for.

tb.start()
fil=open("/home/murtuza/t",‘r’) # I first open a file to read

n=0
while n<1:
    data = fil.read(gr.sizeof_char)  # then read one byte only
    n=n+1
    send_pkt(data) # then send it over the stream to a block that

processes that particular byte.
print “called”

tb.wait()

If you look at benchmark_tx.py program data is read from a file and then
send_pkt() is called. send_pkt() module in transmit_path.py calls
“self.packet_transmitter.send_pkt(payload, eof)” which then calls
send_pkt()
in mod_pkts. Here, the payload is inserted into the message queue by the
statement self._pkt_input.msgq().insert_tail(msg). I want to do
something
similar except for the fact that I want to put the unmodified byte in
the
queue unlike mod_pkts which first uses message_from_string and then
inserts
the msg on to the queue.

If this can be done using file_source then can u tell how?

I am working on something that requires me to do this. May be this is
not an
ideal way of doing it but still I want to know if it is possible.

Thanks,
Ali