Help w/ Codegolf Total Triangles- reading input

Hello all -

I’m getting quite frustrated with a very “easy” part of this
problem…reading the input! Basically, the input is given as so:

1
1 2
1 3 2
1 4 2 1

What I intend to do is read the input line by line, split the lines by
spaces and store each substring as the associated integer. Essentially I
want to end up with a two dimensional array holding the integers shown
above. I’m using the following line of code:

a = readlines.each{|i|i.split(" ").each{|j|j=j.to_i}}

However, when I do a puts I see the following:

puts a[1][1] => 32

GAH! Why is it printing the ascii character value? Do I have a logic
flaw in the way I’m reading the input? Is there a better way to read the
input? Should I just tear my hair out?

Thanks,
Drew

On Sep 23, 2006, at 10:44pm, Drew O. wrote:

a = readlines.each{|i|i.split(" ").each{|j|j=j.to_i}}

You don’t want #each, but rather #map or #collect:

a = readlines.map { |i| i.split(" ").map { |j| j.to_i } }

And just as a point of style, some whitespace in there would read a
whole lot better.

–John

John -

Thanks for the help…and with respect to white space, I apologize, I
was in the codegolf mindset and trying to conserve bytes.
http://www.codegolf.com

Also, can you explain to me the difference between map and each?

John L. [email protected] wrote:

Additional note: it’s probably better to use #scan instead of split
because
then you can make sure to only get the numbers:

a = readlines.map {|line| line.scan(/\d+/).map! {|s| s.to_i}}

Kind regards

robert

On Sep 23, 2006, at 11:12pm, Drew O. wrote:

Thanks for the help…and with respect to white space, I apologize, I
was in the codegolf mindset and trying to conserve bytes.
http://www.codegolf.com

Ah, then the compression is forgiven. :wink:

Also, can you explain to me the difference between map and each?

#each just evaluates the block for each element of the list (or
whatever you’re iterating over). You don’t usually use the return
value of #each.

#map (aka #collect) also evaluates the block for each element, but
returns a new list containing the return value of each evaluation.
It’s good for translating one set of values to another, like you were
doing in your code.

–John

Drew O. wrote:

GAH! Why is it printing the ascii character value? Do I have a logic
flaw in the way I’m reading the input? Is there a better way to read the
input? Should I just tear my hair out?

Well firstly, because as others have mentioned, you were using #each,
so you were getting an array populated with strings:

[“1”, “1 2”, “1 3 2”, “1 4 2 1”]
^
…and the 1-index of the 1-item of the array is a space (" ") – ascii
ordinal 32.

But why doesn’t ruby give you the space – why the ordinal? Because in
1.8, indexing a string by a single integer gives you the ascii ordinal
for that character of the string (this changed in 1.9, now it gives you
the character and you have to explicitly use #ord to get the ordinal).
So, ‘a’[0] => 97. If you ever need to get around that, just make the
indexer into a range: ‘a’[0,1] => a, ‘a’[0…0] => a.

Regards,
Jordan

Devin M. wrote:

Drew O. wrote:

Essentially I
want to end up with a two dimensional array holding the integers shown
above.
Figure out your algorithm first.

Devin -

My first attempt at an algorithm was this:

Work backwards row by row. In each row, compare the current element with
the next, and whichever ever is larger, add this number to the element
in the same index in the next highest row. Eventually, the value in
a[0][0] will be the largest path…does this makes sense? Is it an
effective strategy?

Drew O. wrote:

Essentially I
want to end up with a two dimensional array holding the integers shown
above.
Figure out your algorithm first.

Hi –

On Mon, 25 Sep 2006, Devin M. wrote:

(I’ll have to look at it, myself. :P)

One more hint: You probably don’t need to waste your time with map. Consider:
a=readlines.each{|i|i.split(" ").each{|j|j=j.to_i}}

That just assigns the lines you’ve read in, unchanged, to a. In the
outer each, you split lines and send the results, before you discard
them, to the inner each – where you reuse the identifier j, and then
throw its new value away. Meanwhile, all a cares about is the return
value of readlines.each, which is its receiver.

I think maybe map is indeed called for :slight_smile:

David

Drew O. wrote:

Work backwards row by row. In each row, compare the current element with
the next, and whichever ever is larger, add this number to the element
in the same index in the next highest row. Eventually, the value in
a[0][0] will be the largest path…does this makes sense? Is it an
effective strategy?
Yeah, that does seem like it’ll work. I never thought of it that way.

Think of the forwards algorithm, too. Then determine if the code you
write with the backwards is 8 bytes shorter (to make up for reverse_each
vs each). (I’ll have to look at it, myself. :P)

One more hint: You probably don’t need to waste your time with map.
Consider:
a=readlines.each{|i|i.split(" “).each{|j|j=j.to_i}}
a.reverse_each{|r|p r[0]}
vs:
readlines.reverse_each{|l|l.split(” ")[0].to_i}
Again, try it both ways and see. (Keeping in mind that if the difference
is small, then the winner’s not certain – the little optimizations
could tip it either way.)

I could suggest more things, but I don’t wanna lose my spot. It’s the
one challenge at which I was actually successful. :slight_smile:

Devin
Wow… acting as if I’m an expert after a few little internet
challenges… Well, grain of salt and all that.

[email protected] wrote:

a=readlines.each{|i|i.split(" ").each{|j|j=j.to_i}}
That just assigns the lines you’ve read in, unchanged, to a.
That was a paste-o on my part. My point was that the functional means of
doing things don’t tend to golf well. Compare:
a.map{|b|b.to_i}.each{|c|}
a.each{|b|c=b.to_i}

Devin

Hi –

On Mon, 25 Sep 2006, Devin M. wrote:

[email protected] wrote:

a=readlines.each{|i|i.split(" ").each{|j|j=j.to_i}}
That just assigns the lines you’ve read in, unchanged, to a.
That was a paste-o on my part. My point was that the functional means of
doing things don’t tend to golf well. Compare:
a.map{|b|b.to_i}.each{|c|}
a.each{|b|c=b.to_i}

Doesn’t it depend what you need, though? Also, you can always do the
each-like side-effect stuff with map, but not the map-like stuff with
each.

David

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