Hello! first post to clr. I'm asking about an attempt at a lazy ruby solution to computing fibonacc

Hi, first post to clr here.

I have a guess a haskell bias as that’s the last language I learned,
and now I’m learning ruby.

I was trying to solve project euler problem 2 as an exercise. This is,
sum all the even fibonacci numbers less than 4 million.

There is a solution that works at

http://www.absorbeo.net/2008/01/10/project-euler-problem-2/

however I didn’t quite like it because the test for evenness is in the
fold (haskell speak for inject).

puts a.inject(0) {|s,v|
if v > 1_000_000 then
break s
elsif v % 2 == 0
s+v
else
s
end
}

the haskell solution reads nicer to me

t = ( putStrLn . show . sum . takeWhile (<=4000000) . filter even )
fibs2
fibs2 = 1 : 2 : zipWith (+) fibs2 (tail fibs2)

but it relies on laziness and who knows what other magic.

I decided to see if I could find a ruby solution that was more
haskellish. It turns I can… almost.

There is a ruby library for laziness

http://lazylist.rubyforge.org/

and it would seem to do what I want. But it hangs for some reason.

I have poor sense of ruby culture. Should I report this as a bug? Is
it even a bug? Do people ever use laziness, or is this crazy
experimentation?

Thanks for help and advice!

Code below:

[email protected]:~/thomashartman-learning/ruby/katas/euler>cat
2.rb
require ‘rubygems’
require ‘lazylist’ # http://lazylist.rubyforge.org/

Solve Project Euler problem 2: sum fibonacci numbers <= 4_000_000,

which are even.
fibs = ( LazyList.tabulate(0) { |x| x < 2 ? 1 : fibs[x-2] +
fibs[x-1] } )

fibsUnder4M = ( fibs.partition{ |x| x <= 4_000_000 })[0]
evenFibsUnder4M = fibsUnder4M.select{ |x| x %2 == 0}

problem seems to be with partition

evenFibsLessThanFourMil = ( evenFibs.partition{ |x| x <= 4_000_000 })

[0]

works

puts evenFibsLessThanFourMil.take(1)

hangs

puts evenFibsUnder4M.take(10) # this is ok
puts evenFibsUnder4M.take(11) # this hangs, laptop gets hot, fan turns
on…

exit

this would be the answer to the euler problem, if only there wasn’t

the bug…
result = evenFibsLessThanFourMil.inject(0){ | accum,val | accum + val}

main = puts result
[email protected]:~/thomashartman-learning/ruby/katas/
euler>ruby 2.rb
2
8
34
144
610
2584
10946
46368
196418
832040
… hung…

On Aug 6, 2008, at 08:40 , tphyahoo wrote:

t = ( putStrLn . show . sum . takeWhile (<=4000000) . filter even )
fibs2
fibs2 = 1 : 2 : zipWith (+) fibs2 (tail fibs2)

Gives me hives personally… I’ve never been able to handle the syntax
of haskell.

but it relies on laziness and who knows what other magic.

The laziness I’m fine with… the other magic? not so much.

I decided to see if I could find a ruby solution that was more
haskellish. It turns I can… almost.

Ignoring my haskell bias for a bit… I’d recommend doing this, with
any pairing of languages. Find the idiomatic response appropriate for
the target language and you’ll have a better time.

There is a ruby library for laziness

http://lazylist.rubyforge.org/

I’ve not used this personally, I suspect using it is the problem.

and it would seem to do what I want. But it hangs for some reason.

I have poor sense of ruby culture. Should I report this as a bug? Is
it even a bug? Do people ever use laziness, or is this crazy
experimentation?

Assuming it is a bug, yes, report it. Again, not having used the
library, I can’t really weigh in whether this behavior is a bug or not.

require ‘rubygems’
require ‘lazylist’ # http://lazylist.rubyforge.org/

Solve Project Euler problem 2: sum fibonacci numbers <= 4_000_000,

which are even.
fibs = ( LazyList.tabulate(0) { |x| x < 2 ? 1 : fibs[x-2] +
fibs[x-1] } )

so, according to the doco, tabulate is a generator function that
starts at 0 and yields the block on each successive succ.

(stop with all the parens)

fibsUnder4M = ( fibs.partition{ |x| x <= 4_000_000 })[0]

partition is customized to return two lazy lists, so this should be
fine.

evenFibsUnder4M = fibsUnder4M.select{ |x| x %2 == 0}

likewise, select is customized to return a lazy list. again, fine.

hangs

puts evenFibsUnder4M.take(10) # this is ok
puts evenFibsUnder4M.take(11) # this hangs, laptop gets hot, fan turns
on…

presumably the take actually executes and generates elements from the
lazy list, unwinding back through the select, the partition, and
finally the tabulate block. This all looks kosher to me on the surface
(albeit a bit more complicated than necessary because you’re trying to
match haskell.

So, I would think that you’ve discovered a bug in the LazyList impl,
as your logic seems sound.

Here is my ruby-idiomatic solution to the problem:

sum = 0
fibs.each do |n|
sum += n
end

p sum

=> 4613732

because of the memoization, it runs incredibly fast. If I wasn’t
allowed to predetermine the upper bound of the calculation, I’d wrap
that up in a simple loop with a conditional… Nothing fancy.

It is implementation failure, you are right.
LazyList::Enumerable has buggy select which works as follows:

So it search first true occurence and returns new object.

list = LazyList.tabulate(0) { |x| x }
=> [… ]
less_than_three = list.select { |x| x < 3 }
lest_than_three.take(0);lest_than_three.take(1);lest_than_three.take(2)
less_than_three.tail
=> [1, 2,… ]
less_than_three.tail.tail
=> [2,… ]
less_than_three.tail.tail.tail

Hangs

So this should return lazy tail (which is empty, infinite loop occurs).

By the way, you are hunting ants with an rpg:P

Best Regards

Maciej

Maciej Tomaka wrote:

By the way, you are hunting ants with an rpg:P

He is hunting ants with a role playing game? :wink:

There is an archive kept of threads and you can find some of this
discussed already by searching through it. As this is your first, post,
allow me to give it to as a freebie.

http://www.ruby-forum.com/forum/4?filter=fibonacci

Lloyd L. wrote:

Maciej Tomaka wrote:

By the way, you are hunting ants with an rpg:P

He is hunting ants with a role playing game? :wink:

:slight_smile: Have you ever seen Duke Nukem? RPG was a rocket launcher :wink:

On Wed, Aug 6, 2008 at 3:51 PM, Ryan D. [email protected]
wrote:

$fib = {} # simple memoization
end

p sum

=> 4613732

because of the memoization, it runs incredibly fast. If I wasn’t allowed to
predetermine the upper bound of the calculation, I’d wrap that up in a
simple loop with a conditional… Nothing fancy.

Personally, I like a Ruby memoizing solution, but seeing some other
lazy Ruby projects in a quick Google search, I whipped this up:

require ‘lazy_stream’

even = lambda{|int| int[0] == 0}
under_4_million = lambda{|int| int <= 4_000_000 }

fibonacci = lambda{|array, index|
index < 2 ? 1 : array[index - 2] + array[index - 1]
}

create a “lazy stream” that generates the fibonacci sequence

fibs = LazyStream.new(fibonacci)

create a filtered lazy stream of even fibonacci numbers

even_fibs = LazyStream.filter(fibs, even)

sum the even fibonacci numbers that are less than 4,000,000

sum = 0
even_fibs.each_while(under_4_million){|f| sum += f}
puts sum

=> 4613732

And the evil class that makes it “work”:

A very simple lazy generator based on Array

class LazyStream < Array

When creating a LazyStream, supply a generator lambda.

The generator should take as parameters the stream and the index.

def initialize generator
@generator = generator
end

Override the basic array [] to generate as necessary.

def
if index.is_a? Range
index.map{|i| self[i]}
else
(self.fetch(index) rescue nil) ||
self[index] = @generator.call(self, index)
end
end

Loop through the stream until the value evaluates the block to

false.
def each_while filter
i = 0
loop do
break unless filter.call(self[i])
yield self[i]
i += 1
end
end

Create a new stream that applies a filter to an existing stream.

def self.filter other_stream, filter
new_stream = new lambda{|s, index|
v = nil; @other_index ||= 0

  index.times{|n| new_stream[n]} if index > new_stream.size

  loop{
    v = other_stream[@other_index]
    @other_index += 1
    break if filter.call(v)
  }
  v
}

end

private

Move the basic array []= to private so people don’t muck around with

it :slight_smile:
def []=(index, value)
super(index, value)
end
end

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