Hash name increment on iteration?

Ruby
1

Is it possible to add to the name of a hash while running through an
iteration? What I’m trying to achieve:

SomeArray.each do |i, name, content|
info[i+1] = { “name” => name, “content” => content }
end

So that I can call, for example info[1] [name] or info[5][content]…

2

On 08.04.2010 03:27, Shaz wrote:

Is it possible to add to the name of a hash while running through an
iteration? What I’m trying to achieve:

SomeArray.each do |i, name, content|
info[i+1] = { “name” => name, “content” => content }
end

So that I can call, for example info[1] [name] or info[5][content]…

Make info an Array and just use

info << { :name => name, :content => content }

Kind regards

robert

3

Is this what you want?

SomeArray.each_with_index do |(name,content),i|
…
end

4

Shaz wrote:

Each with index worked for me - didn’t realize each variable in the
array has an index that can be called.

Not exactly. The ‘each_with_index’ method just yields the array index to
the block being called.

Inside it will be implemented something like this:

module Enumerable
def each_with_index
i = 0
each do |elem|
yield elem, i
i += 1
end
end
end

But you could consider it like this:

class Array
def each_with_index
size.times do |i|
yield self[i], i
end
end
end

5

On 8 Apr, 08:44, Brian C. [email protected] wrote:

Is this what you want?

SomeArray.each_with_index do |(name,content),i|
…
end

–
Posted viahttp://www.ruby-forum.com/.

Each with index worked for me - didn’t realize each variable in the
array has an index that can be called. Thanks!

6

On Sun, Apr 11, 2010 at 5:32 PM, Li Chen [email protected] wrote:

end

end

  1. which one is the reciever for “each”?
  2. which one is the reciever for “size”?

When there’s no explicit receiver, the method call happens on the
object that is “self” at that point.

Jesus.

7

Jesús Gabriel y Galán wrote:

On Sun, Apr 11, 2010 at 5:32 PM, Li Chen [email protected] wrote:

� � end
� end

  1. which one is the reciever for “each”?
  2. which one is the reciever for “size”?

When there’s no explicit receiver, the method call happens on the
object that is “self” at that point.

Jesus.

Hi Gabriel,

Where can I find more info about method call on implicit receiver?

Li

8

On 4/11/10, Li Chen [email protected] wrote:

Where can I find more info about method call on implicit receiver?

Seems like we’ve had a number of newbies who’ve been perplexed about
this recently. Maybe this should be in the faq. Isn’t there a faq
somewhere?

9

Brian C. wrote:

Inside it will be implemented something like this:

module Enumerable
def each_with_index
i = 0
each do |elem|
yield elem, i
i += 1
end
end
end

But you could consider it like this:

class Array
def each_with_index
size.times do |i|
yield self[i], i
end
end
end

Hi Brian,

Just some follow-up questions for these codes:
I recall the the method call in Ruby follow this format:
“receiver.method”
So

  1. which one is the reciever for “each”?
  2. which one is the reciever for “size”?

Thanks,

Li